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  • 1 answers

Jaya Chaudhary 5 years ago

Answer From the figure: x + 50o = 180o (Linear pair) x = 180o - 50o x = 130o And, y = 130o (Vertically opposite angles) Now, x = y = 130o (Alternate interior angles) Hence, The theorem says that when the lines are parallel, that the alternate interior angles are equal. And thus the lines must be parallel. AB || CD
  • 3 answers

Divya Raj 5 years ago

Curved surface area of cylinder= 2πrh 88cm^2 = 2*22/7*r *14cm 88cm^2 = 44*2r 88cm^2/88cm =r r= 1 cm Diameter= 2r = 2*1= 2 cm ans.

Krishvi Anand 5 years ago

1 CM radius and therefore diameter will be 2r= 2×1=2 cm

Khilesh Kumar 5 years ago

1cm radius So, 2cm diameter
  • 2 answers

Kuldeep Thakur 5 years ago

Vice versa is a latin phrase that means ' The other way round '

Pranav Mishra 5 years ago

It mean that reverse of a thing that you had said before or hindi me bola jaaye to ulat palat krdena
  • 5 answers

Shreya Tiwari 5 years ago

area = √s(s-a)(s-b)(s-c) S=a+b+c/2

Bbch Fbx 5 years ago

S=a+b+c/2 area = √s(s-a)(s-b)(s-c)

Naman Singh 5 years ago

S=a+b+c/2and then Area =under rogt(s-a)(s-b)(s-c).

Samruddhi ? 5 years ago

Under root s(s-a)(s-b)(s-c)

Shooter Sherni 5 years ago

Write Heron's formula
  • 1 answers

Priyal Gupta 5 years ago

If you are asking about it's p/q form then it is equal to 41/333
  • 1 answers

Mahrosh Khan 5 years ago

Answer r/s = 1/2π Explanation When square sheet of paper is converted into a cylinder by rolling, circumference of base is equal to side od square. Let s be side of square and r be radius of base of cylinder. s = 2πr r/s = 1/2π Hence, ratio of the base radius of cylinder to the side of square is 1:2π.
  • 3 answers

Anushka Jalan 5 years ago

Yes as can be written as p/q

Sarita Panda 5 years ago

5918/1000=>2959/500

Yash Raj 5 years ago

Yes as it can represented as p/q
  • 2 answers

Japnidh Kaur 5 years ago

You can check in this app only by opening NCERT solutions in any chapter.

Japnidh Kaur 5 years ago

Of which subject?
  • 0 answers
  • 3 answers

Naman Singh 5 years ago

3.46

Krish Achra? 5 years ago

3

Mohit Kumar 5 years ago

2√3
  • 2 answers

Dhruv Rangari 5 years ago

I know it is a question of circles where you have been given length of chord 24 cm and radius 13 cm so you have to find distance between the chord and centre so the answer is 5 because it is the triplet

Sarita Panda 5 years ago

It can be various number. One type of Pythagorean triplet is (13,12,5)where 13 is the hypothenues.
  • 1 answers

Alphonsa Jimmy 5 years ago

When two lines intersect each other, then the opposite angles, formed due to intersection are called vertical angles or vertically opposite angles. A pair of vertically opposite angles are always equal to each other. Also, a vertical angle and its adjacent angle are supplementary angles, i.e., they add up to 180 degrees. For example, if two lines intersect and make an angle, say X=45°, then its opposite angle is also equal to 45°. And the angle adjacent to angle X will be equal to 180 – 45 = 135°.
  • 1 answers

Alphonsa Jimmy 5 years ago

Two angles are Adjacent when they have a common side and a common vertex (corner point) and don't overlap.
  • 4 answers
TSA of cuboid is 2(lb+bh+HL) CSA of cuboid is 2h(l+b)

Raghuram Ramya 5 years ago

TSA of cuboid is 2(lb+bh+HL) CSA of cuboid is 2h(l+b)

Naman Singh 5 years ago

Bro if you want Total surface area of cuboid is 2(lb+bh+hl) Lateral surface area of cuboid is 2(l+b)*h

Niharika Sharma 5 years ago

2(lb+bh+hl)
  • 1 answers

Khushi Kaur 5 years ago

(3/4)6*(16/9)5 =(4/3)X+2 (3/4)6*(4/3)10=(4/3)X+2 (4/3)-6*(4/3)10=(4/3)X+2 (4/3)-6+10=(4/3)X+2 (4/3)4=(4/3)X+2 SINCE BASES ARE EQUAL X+2=4 X=2
  • 3 answers
find a&b , if 2-√5 =a√5 + b 2+3√5

Khushi Kaur 5 years ago

Let r cm be the radius of the base and h cm be the height of the cylinder, Then, total surface area of cylinder = 2πr (r + h) Curved surface area of cylinder = 2πrh  We have,  Curved surface area = 1/3(Total surface area) = 1/3 x 462 cm2 = 154 cm2  ⇒  2πrh = 154  Also, 2πrh + 2πr2 = 462    ⇒ 154 + 2πr2 = 462 ⇒  2πr2 = 462 - 154 = 308 cm2 2 x 22/7 x r2 = 308 ⇒  r2 = 308 x 7/2 x 22 = 72  ⇒  r = 7 cm Again 2πrh = 154    ⇒ 2 x 22/7 x 7 x h = 154  ⇒ h = 154/2 x 22 = 7/2 cm  Volume of the cylinder =  πr2h = 22/7 x 7 x 7 x 7/2 = 539 cm3

Palak Gupta 5 years ago

Given, total surface area of cylinder = 462 square cm. Also, CSA of cylinder = 3 TSA of ccylinder ⇒TSA=2πrh+2πr2 ⇒TSA=CSA+2πr 2 ⇒TSA= 3TSA +2πr 2 ⇒ 32TSA ​ =2πr 2 ⇒ 3TSA ​ =πr2 ⇒ 3462 ​ = 722 ×r 2 ⇒r=7cm Now, CSA of cylinder = 3 TSA of ccylinde = 3462 ​ =154cm 2 ⇒2πrh=154 ⇒2× 7 22 ×7×h=154 ⇒h= 27cm Therefore, volume of the cylinder =πr 2 h= 722​ ×7 2 × 27 ​ =539cm 3 Hence, volume of the solid cylinder is 539cm 3 .
  • 2 answers

Palak Gupta 5 years ago

Let the length be 4x Let the breadth be 2x Let the height be x Surface area=2(lb+bh+hl) =2(8x²+2x²+4x²) =28x²=1372 so x²=49 and x=7 So length=4x=28cm breadth=2x=14cm &. height=x=7cm I hope the above solution will help you...

Khushi Kaur 5 years ago

Given the surface area of cuboid as 1372cm2 , length are in the ratio of 4:2:1 Let the lenght, breadth and height of cuboid are 4x ,2x and x respectively. surface area of cuboid = 2(lb+bh+lh) where l= length of cube , b = breadth , h = height of cube surface area of cuboid = 2(lb+bh+lh) 1372= 2(4x*2x+2x*x+4x*x) 1372= 2(8x2+2x2+4x2) 1372= 2*14x2 1372= 28X2 1372/28 = X2 X2 = 49          // TAKING SQUARE ROOT // √X2 =√49 X = 7 ​length of cuboid is 4x 7 =28cm
  • 2 answers

Palak Gupta 5 years ago

Given: Two circles with centers A and B, which intersect each other at C and D. To prove : ∠ACB=∠ADB Construction : Join AC,AD,BD and BC. Proof : In triangles ACB and ADB, we have AC=AD ...Radii of the same circle BC=BD ...Radii of the same circle AB=AB ...Common Therefore, by SSS criterion of congruence, △ACB≅△ADB ⇒∠ACB=∠ADB ...CPCT

Khushi Kaur 5 years ago

Given : Two intersecting circles, in which OO′ is the line of centres and A and B are two points of intersection.  To prove : ∠OAO′ = ∠OBO′  Construction : Join AO, BO, AO′ and BO′.  Proof : In ∆AOO′ and ∆BOO′, we have  AO = BO [Radii of the same circle]  AO′ = BO′ [Radii of the same circle]  OO′ = OO′ [Common]  ∴ ∆AOO′ ≅ ∆BOO′ [SSS axiom]  ⇒ ∠OAO′ = ∠OBO′ [CPCT]  Hence, the line of centres of two intersecting circles subtends equal angles at the two points of intersection. Proved.Read more on Sarthaks.com - https://www.sarthaks.com/12080/prove-that-line-centres-intersecting-circles-subtends-equal-angles-points-intersection
  • 1 answers

Palak Gupta 5 years ago

In Triangle ABC D is the mid-point of AB E is the mid point of AC ∴ DE||BC and DE= 1/2 BC So DE=1/2 ×8.2 DE=4.1 cm
  • 2 answers

Vanshika Jain 5 years ago

Class marks=(upper limit+lower limit)/2 =120+100/2=220/2=110 is the ans

Khushi Kaur 5 years ago

Class mark = (Lower limit + Upper limit)/2                    = 100 + 120/2  = 110
  • 2 answers

Saniya .. 5 years ago

A chords is a line segment joining two points on the curve.

Suchitra Sen 5 years ago

Chord:A line segment joining any two points on the circlee.
  • 3 answers

Abdul Bashit 5 years ago

Total surface area of cuboid is 2(lb+bh+hl)

Abhishek Singh 5 years ago

2(lb+bh+hl)

Bharat Sharma 5 years ago

2(lb×bh×hl)

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