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7.2
  • 1 answers

Gulam Hussain 5 years ago

Hindi language
  • 3 answers

Gulam Hussain 5 years ago

7.2

Vidhi Verma 5 years ago

Then wait plz tell whole question

Palak Kalia 5 years ago

plz send the answer of sample papers
  • 3 answers

Nithya Sri 5 years ago

All formulas are important . Nothing is left as unimportant in mathematics because it will carry the basic Knowledge for higher grades
Most important learn the formulas TSA,LSA AND CSA OK

Vidhi Verma 5 years ago

Most imortant to learn all formulas of CSA, LSA, Volumes
  • 5 answers

Vanshika Jain 5 years ago

√s(s-a)(s-b)(s-c)

Tarun Chaudhary 5 years ago

Herons formula is used to find the area of a triangle whose all the three sides are given. It's formula is s=a+b+c/2 Area=√s(s-a)(s-b)(s-c)

Aman Kumar 5 years ago

Root s(s-a) (s-b) (s-c)

Mishtha Sharma 5 years ago

area=s (s-a)(s-b)(s-c)

Vishwas Prabhu 5 years ago

In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle when the length of all three sides are known. Unlike other triangle area formulae, there is no need to calculate angles or other distances in the triangle first.
  • 0 answers
  • 2 answers
1. Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centres. Solution: To recall, a circle is a collection of points whose every point is equidistant from its centre. So, two circles can be congruent only when the distance of every point of both the circles are equal from the centre. Ncert solutions class 9 chapter 10-1 For the second part of the question, it is given that AB = CD i.e. two equal chords. Now, it is to be proven that angle AOB is equal to angle COD. Proof: Consider the triangles ΔAOB and ΔCOD, OA = OC and OB = OD (Since they are the radii of the circle) AB = CD (As given in the question) So, by SSS congruency, ΔAOB ΔCOD ∴ By CPCT we have, AOB = COD. (Hence proved). 2. Prove that if chords of congruent circles subtend equal angles at their centres, then the chords are equal. Solution: Consider the following diagram- Ncert solutions class 9 chapter 10-2 Here, it is given that AOB = COD i.e. they are equal angles. Now, we will have to prove that the line segments AB and CD are equal i.e. AB = CD. Proof: In triangles AOB and COD, AOB = COD (as given in the question) OA = OC and OB = OD (these are the radii of the circle) So, by SAS congruency, ΔAOB ΔCOD. ∴ By the rule of CPCT, we have AB = CD. (Hence proved)

Shreekanth Cm 5 years ago

Woooooowwwwww
  • 1 answers

Harsh Raj 5 years ago

write the from of p/q 0.57
  • 1 answers

Roopak Kumar 5 years ago

When two angles and side included in between these angles of one triangle are same as another one, both these triangle are Congruent. This criteria of congruency is knows as ASA criterion as a side included between two angles are all same.
  • 3 answers
Priyanshu bro correct

Priyanshu Bro 5 years ago

31/50,32/50,33/50,34/50,35/50.

Raj Sharma 5 years ago

012
  • 3 answers

Pooja Verma 5 years ago

Range

Adithi K.Iyer 5 years ago

The difference between upper limit and lower limit is called RANGE

Avika Gupta 5 years ago

Class interval
  • 2 answers

Payal Jaiswal 5 years ago

As x+y=180o⇒2x​+2y​=90o ⇒∠DPA=90o=∠SPQ (vertically opp) ∠SRQ=90o=∠PSR=∠PQR Also In △ASB′y′&′B′ are distinction ∴  As is d if from BS  hence PQRS is A rectangle. 

Parul Prajapati 5 years ago

Hm
  • 1 answers
ՏO Tᕼᗴ ᑫᑌᗴՏTIOᑎ ᗯᗩՏ - Show that the angles of an equilateral triangle are 60° each. Solution: Let ABC be an equilateral triangle Here, BC = AC = AB (Since the length of all sides is same) ⇒ A = B =C (Sides opposite to the equal angles are equal.) Also, we know that A+B+C = 180° ⇒ 3A = 180° ⇒ A = 60° ∴ A = B = C = 60° So, the angles of an equilateral triangle are always 60° each.
6.3
  • 1 answers

Utkarsh Goyal 5 years ago

We can that = 6.300000000000000000000000000000 and infinite
  • 1 answers

Kiron Maharana 5 years ago

-2/1×7/7=-14/7 , -1/7×7/7=-7/7 Ans=> -8/7, -9/7, -10/7, -11/7, -12/7, -13/7.

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