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Explain the statement with examples from the text . Give the answer into 80 words​.

A metaphor and a simile are quite similar actually. A metaphor also uses compares to things that are in no way similar. It does so to bring out the symbolism. A metaphor is a word or phrase used to show its similarity to another thing. It helps to explain an idea, but if you take a metaphor at its literal meaning it will sound absurd.

An example of a metaphor is “Alex is a chicken”. Literally, this sounds so very absurd. But this is a metaphor which suggests that Alex is a coward, or frightened. It compares or implies that Alex is a chicken to bring out the symbolism. Some other examples are ‘love is a battlefield”, “all the world’s a stage”, “that technology is a dinosaur” etc.

 

While a simile and metaphor seem to be very similar, there is one basic difference between the two. In a simile, the comparison happens with the help of the words “as” and “like”. A metaphor will not have either of those two words.

ANSWER 10 volume H2​O2​ solution means 1 mL of 10 volume H2​O2​ solution gives 10 mL of oxygen.

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5

What is a exercise of chapter 7 data for variable q&a

4/75

The arrangement of the given rational number is as per the rule of distributive law over subtraction.

Now take out 1/5 as common.

Then,

= 1/5 [(2/15) – (2/5)]

The LCM of the denominators 15 and 5 is 15

(2/15) = [(2×1)/ (15×1)] = (2/15)

and (2/5) = [(2×3)/ (5×3)] = (6/15)

= 1/5 [(2 – 6)/15]

= 1/5 [-4/15]

= (1/5) × (-4/15)

= -4/75

Take out common 1/5×2/5(1/3-1)= 2/25×(-2/3)=-4/75

The School Boy – Summary The School Boy poem is written by William Blake. The poem is about a schoolboy who is unhappy. He says that his childhood is crumpled for the sake of learning and teaching. The boy likes mornings, trees, and birds. He loves being in nature. However, due to his school, his mornings are unpleasant and unhappy. He does not like going to school and is not interested in studies and books. We all know that the pleasure of childhood lies in being free and happy like a bird. The poet here compares a child in school as a bird in a cage. He thus says that as a bird is unhappy in the cage so is a child in school. He says that a child who is scared by his parents and teachers cannot be happy and joyful. The poet further says that the parents should not deprive a child of joy and freedom for the sake of studies. Depriving them of joy and freedom is similar to deprive the world of its spring. The poet also compares it with nipping the buds and flowers from the plants. He is of the opinion that this world will be a sorrowful place in the absence of a happy childhood. The poet beautifully compares it with nature. He says that without a happy childhood, we shall only have a winter of sorrow. We shall never be able to experience the summer of joy. The poem teaches us that being parents we shall take due care of our children. It is our duty to see that our children are happy, joyful, and free. If we want our generations to be happy and prosperous we need to make their childhood a happy one.

The poem throws light on the mindset of a school boy. He is unhappy. He loves outdoor life. He hears the birds sing. The blowing of horn by the huntsmen pleases him. He wants to enjoy the company of the skylark. But he can find such joy only on a summer morning.

Instead of living like a free bird, the boy is made to go to school. It makes him sad. He hates going to school because of his cruel old teacher. There the small children spend the day from morning to evening and get disappointed.

Sometimes the boy sits for hours with his head hanging down but he is caged. He finds no joy in reading his book. The school is a cheerless place for him. He gets fed up with the shower of words from his teacher.

The boy compares himself to a bird who is bom free to fly and enjoy life but he is caged. He cannot sing in a cage. The boy has the feeling of being a prisoner at school. He is all the time afraid of the teacher. As a caged bird he lets his wings droop down and forgets to share the joy of spring.

The poet calls upon the parents not to be so harsh or cmel to the children. School going kids are as delicate as birds and flowers. They need fresh air and free movement to grow healthy and happy. Keeping them under excess cage will make them unhappy. If a plant is denied air and is kept in dark, it won’t grow well and never bear fruit.

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All positive and negative numbers including zero is called integers e.g 1 2 3 4

Collection of all positive and negative numbers including zero are called integers. ⇒ Numbers …, – 4, – 3, – 2, – 1, 0, 1, 2, 3, 4, … are integers.

Human resources are important because the development of other resources solely depends upon this resource as humans have knowledge, skill, and technology to develop other resources.

The wolves raised Mowgli in the forest

The Indian society  was trapped in absurd customs like Sati,  Slavery ,female foeticide centuries., ignorance, superstitious beliefs , discrimination through caste system etc which were the hurdles for it's development and also were the bigger causes for its colonisation by Britishers .The enlightenment in the latter years gave birth to mass awakening against the British oppression and evil customs.To clean Indian society from every ignorance the social reformers started various movements in India.

What is meaning of varna vichhad in sanskrit

Hello harsh dev jha hi

Coal tar is a thick dark liquid which is a by-product of the production of coke and coal gas from coal. It has both medical and industrial uses. It may be applied to the affected area to treat psoriasis and seborrheic dermatitis (dandruff).

Coal tar is made up by mixing the compounds of coke and coal gas. It is mostly used as a raw material in road formation.It also has a great contribution in medicinal use.

Friction is a force that resists the relative motion between two objects or materials. The causes of this resistive force are molecular adhesion, surface roughness, and deformations. Adhesion is the molecular force resulting when two materials are brought into close contact with each other.

Friction is a force that resists the relative motion between two objects or materials. The causes of the resistive force of friction are:

• Molecular Adhesion
• Surface Roughness
• Plowing effect

When we try to move one object over another object, the irregularities present on their surface get entangled or  locked with one another. The interlocking of irregularities of the two surfaces opposes the motion of one object over the other and give rise to force of friction.

Friction is caused by the interlocking of irregularities in the surface of two objects which are in contact with each other. To move one object over the other ,we have to apply a force to overcome interlocking of the irregularities in their surfaces.

More the roughness of a surface larger is the number of irregularities on its surface and has greater will be the friction does the force of friction.The force friction is greater if very rough surfaces are involved.

Perimeter=100cm Side of square=100/4 =25 cm Area of square =side×side 25×25=625 cm sq Area of parellogram =base×height Base =length of parellogram=A/h =625/50=12.5 cm

Rhombus Solve for  perimeter P ≈ 44.72 cm p Diagonal cm q Diagonal cm Using the formulas P = 4 a a = p 2 + q 2 2 Solving for P P = 2 p 2 + q 2 = 2 · 10 2 + 20 2 ≈ 44.72136 cm

Diagonal of rhombus = 12cm and 16cm

half of diagonal = 6cm and 8cm

by using Pythagoras theorem

at the point o where diangonals are meet at that point there are angle formed 90°
so,

a (side) of rhombus = √p² + b²

a = √6² + 8² = √36+64 =√ 100 = 10cm

now , as we know that Perimeter of rhombus

= 4a = 4×10 = 40cm Ans

Let one diagonal = 3X, then other diagonal will be= 4X

Area of Rhombus = d₁*d₂/2 = 54 cm² (given)

or 3X * 4X /2= 54 cm²

or 6 X² =54cm²

or X = Sqrt (54/6) =3 cm

Therefore d₁ = 9 d₂ =12

As diagonals are perpendicular bisector of each other

 

Side of a rhombus = Sqrt { (d₁/2)²+(d₂/2)²}

side of rhombus = sqrt{(9/2)²+(12/2)²} = Sqrt ( 81/4 + 144/4)= Sqrt(225/4)

or Side = 15 / 2 = 7.5 cm (Ans)

As diagonals of Rhombus are perpendicular bisector of each other

(Side of a rhombus )²= (d₁/2)²+(d₂/2)²

Here given d₁ = 24 cm Side = 13 cm

Therefore 13²= (24/2)² + (d₂/2)²

or d₂/2 = Sqrt(169-144) = Sqrt (25) = 5

or d₂ = 10 cm

Therefore Area of the Placard = d₁*d₂/2 = 24 * 10 /2 = 120 cm²

Cost of painting one side = 5.50 * 120 = Rs 660

Cost of painting both sides = Rs 660 x 2 = Rs 1320 (Answer)

In a parallelogram sum of the adjacent angles

equals supplementary.

opposite angles are equal.

Let the smaller angle = x°

larger angle = twice the smaller angle - 30°

=2x° - 30°

x° +2 x° - 30 = 180°

3x° = 180 + 30

3x = 210

x = 210 / 3

x = 70°

Therefore,

smaller angle = x = 70°

larger angle = 2x - 30

= 2 × 70 - 30

= 140 - 30

= 110°

Required parallelogram angles are 70° , 110° ,

70° , 110°
 

Radius of circle = 7cm
Circumference = 2πr = 2 x 22/7 x 7 = 44 cm

Circumference of circle = Perimeter of rhombus
Perimeter of rhombus = 44 cm

Let the side of rhombus be "a"

4a = 44
a = 11 cm

Hence, your answer is 11 cm (side of rhombus).

ANSWER Since opposite angles of a parallelogram are equal. Therefore, 3x−2=50−x⇒x=13 (3x−2)∘=3(13)−2=37∘ The measures of the adjacent angles of a parallelogram add up to be 180 degrees, or they are supplementary. Another angle =180−37=143∘ The measure of each angle of the parallelogram. 37∘,143∘,37∘,143∘

This is rong

In every rhombus, diagonal are perpendicular and bisect each other

Take rhombus as ABCD and bisecting point of diagonals as O

In every rhombus all sides are equal

So AB=BC=CD=DA=5cm

One diagonal is 6cm let AC

OA=OC=3cm

Since it is perpendicular so Pythagorean property applies

(OA)^2+(OB)^2=(AB)^2

=3^2+OB^2=5^2

=9+OB^2=25

=OB^2=25-9=16

=OB=4

Since OB+OD=BD

Then 4cm+4cm=8cm....OB and OD are equal

Area of rhombus=1/2×(d1×d2)

=1/2×(6×8)

=24cm2

GIVEN :-

 

• diagonal of rhombus (D1) = 40 m.
• Area of rhombus = 500 m².
• Cost of plugging the field = Rs. 2.50 /m².

 

TO FIND :-

 

• The other diagonal (D2) .
• Total cost of ploughing the field.

 

SOLUTION :-

 

___________________

 

 

Let the altitude be x.

Then base be 2x.

Area = 288 cm²

 

ATQ,

Area = Base × Height/Altitude

288 cm² = 2x × x

288 cm² = 2x²

2x² = 288 cm²

x² = 288 cm² ÷ 2

x = square root of 144 cm²

x = 12 cm

.°. Base = 2x

= 2 × 12 cm

= 24 cm

Altitude= x

= 12 cm

A n s w  e r

Total sum of the pentagon is 540 degree
Three angles 90degree each
=3×90=270
Let Other two angles of same measure=x
Total sum=540
270+2x=540
2x=540-270
2x=270
X=135
Other two angles are 135 degree each

Drip system

There is network of narrow pipes with small holes in the fields.When water flows through the narrow pipes,it fall drop by drop at the position of roots of the plants.This water is absorbed by the soil in the root zone of the plants and utilised by the plant.There is no wastage of irrigation of water.

Advantages

1)It provides water to plants drop by drop.So water is not wasted at all.

2) It minimises the use of water in agriculture.It is useful in those regions where the availability of water is poor.