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Ask QuestionPosted by Swastik Surve 7 years ago
- 3 answers
Posted by Suraj Chaudhary 7 years ago
- 1 answers
Posted by Tanishq Borse 7 years ago
- 1 answers
Ram Kushwah 7 years ago
L= 4 cm and B= 8 cm
area = L X B = 4 x 8 = 32 cm2
Perimeter = 2x( L +B)
=2x(4 +8) =2 x 12 =24 cm
Posted by Rohan Gangan 5 years, 8 months ago
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Posted by Parvej Alam 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
In {tex}\triangle {/tex}YCB , we have
{tex}\tan 45 ^ { \circ } = \frac { B C } { Y C }{/tex}
{tex}1 = \frac { x } { Y C }{/tex}
YC = xm
{tex}\Rightarrow {/tex} XA = x m
In {tex}\triangle {/tex}XAB, {tex}\tan 60 ^ { \circ } = \frac { A B } { X A }{/tex}
{tex}\sqrt { 3 } = \frac { x + 40 } { x }{/tex}
{tex}\sqrt { 3 } x = x + 40{/tex}
{tex}x \sqrt { 3 } - x = 40{/tex}
{tex}x = \frac { 40 } { \sqrt { 3 } - 1 } \times \frac { \sqrt { 3 } + 1 } { \sqrt { 3 } + 1 }{/tex}
{tex}= 20 ( \sqrt { 3 } + 1 ){/tex}
{tex}= ( 20 \sqrt { 3 } + 20 ){/tex}
{tex}\therefore {/tex} height of the tower AB = x + 40
{tex}= 20 \sqrt { 3 } + 20 + 40{/tex}
{tex}= 20 \sqrt { 3 } + 60{/tex}
{tex}= 20 ( \sqrt { 3 } + 3 ){/tex}
In {tex}\triangle {/tex} XAB,
{tex}\sin 60 ^ { \circ } = \frac { A B } { B X }{/tex}
{tex}\frac { \sqrt { 3 } } { 2 } = \frac { A B } { B X }{/tex}
{tex}B X = \frac { 20 ( \sqrt { 3 } + 3 ) 2 } { \sqrt { 3 } }{/tex}
{tex}= 40 ( \sqrt { 3 } + 1 ){/tex}
{tex}= 40 \times 2 \cdot 73{/tex}
= 109.20 m
Posted by Pankaj Pankaj 7 years ago
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Posted by Aitesam Khan 7 years ago
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Posted by Kshitiz Mishra 7 years ago
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Posted by Jasmeen Bano 7 years ago
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Posted by Muskan Jain 7 years ago
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Posted by Daljit Singh 7 years ago
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Posted by Daljit Singh 7 years ago
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Posted by Daljit Singh 7 years ago
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Posted by Daljit Singh 7 years ago
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Posted by Daljit Singh 7 years ago
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Posted by Daljit Singh 7 years ago
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Posted by Purushottam Rai 7 years ago
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Posted by Arya Bangar 7 years ago
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Ram Kushwah 7 years ago
Like 1.3482620...................... or
5.678923...............................
Posted by Tharun Prakash 7 years ago
- 2 answers
Ram Kushwah 7 years ago
Anand answered 16 correct and 9 wrong
so score= 16 x4 + 9x(-2)
=64-18 =46
Posted by Shreejay Kabra 7 years ago
- 2 answers
Posted by Arunitha Mohan 7 years ago
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Posted by Shreyas Etigowni 7 years ago
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Posted by Praveen Gupta 7 years ago
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Posted by Twinkle Nagpal 7 years ago
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Twinkle Nagpal 7 years ago
Posted by Rajvi Gonawala 7 years ago
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Posted by Jancy Dais 7 years ago
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Krrish Tyagi 7 years ago
Posted by Jancy Dais 7 years ago
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Posted by Navya Sree 7 years ago
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Yogita Ingle 7 years ago
The lateral surface area is the area of all sides excluding the area of the base.
Total surface area of any solid is the sum of areas of all the faces of the solid.
TSA = Total surface are = LSA(Lateral surface area ) + Area of Top + Area of Bottom
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Yashodeep Patil 7 years ago
0Thank You