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Ask QuestionPosted by Arif Siddiqui 6 years, 11 months ago
- 2 answers
Posted by Sukh Preet Singh Singh 6 years, 11 months ago
- 1 answers
Posted by Kuldip Kute 6 years, 11 months ago
- 4 answers
Posted by Shiv Shankar Maurya 5 years, 8 months ago
- 2 answers
Ram Kushwah 6 years, 11 months ago
Here a= 60cm,b=45 cm,c=32 cm
volume of wood required = surface area x thickness
SA=2(ab+bc+ca)
=2( 60x45+45x32+32x60)
=2(2700+1440+1920)
=2x6060=12120 sq cm
Volume of woof=12120 x2.5 =30300 cm cube
Inner walls of the the box
a=60-2x2.5=55 cm b=45-5=40 cm c=32-5=27 cm
volume or capacity= abc=55 x 40x27=59400 cm cube
Posted by Yash3K Khan 6 years, 11 months ago
- 1 answers
Posted by Diwakar Verma 6 years, 11 months ago
- 2 answers
Diwakar Verma 6 years, 10 months ago
Yogita Ingle 6 years, 11 months ago
One side rhombus = 13 cm
Length of one diagonal = 10 cm
Property to use: diagonals of rhombus bisect each other at 90 degree
taking 1/4 portion of rhombus (triangle)
base = 5 cm (half of diagonal)
hypotnuse = 13 cm
for perpendicular use pythagoras theorem
h2 = b2 + p2
on putting the values in the equation and then solving it we get perpendicular(p)= 12cm
therefore diagonal = 2p= 24cm
Posted by Mukul Garg 6 years, 11 months ago
- 0 answers
Posted by Kashish Bhambhani 6 years, 11 months ago
- 2 answers
Posted by Shashidhar Sankonatti 6 years, 11 months ago
- 1 answers
Gaurav Seth 6 years, 11 months ago
96abc/144×3(a-4)×5(b-6)/(a-4)(b-6) :
cut (a-4) and (b-6) = 2abc × 3 × 5/3 :
cut 3 and 3 :
Ans. 10 ABC
Posted by Krithik . B 6 years, 11 months ago
- 0 answers
Posted by Arsh Belim 6 years, 5 months ago
- 1 answers
Posted by Aman Khan 6 years, 11 months ago
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Posted by Pawan Pandey 6 years, 11 months ago
- 1 answers
Posted by Sunita Malhotra 6 years, 11 months ago
- 0 answers
Posted by Harmeet Kaur 6 years, 11 months ago
- 1 answers
Yogita Ingle 6 years, 11 months ago
Let the common multiple is x
Then angle of quadrilateral are 2x, 3x, 6x and 7x
Sum of angles of quadrilateral = 360°
2x + 3x + 6x + 7x = 360°
18x = 360°
x = 360/18
x = 20°
Angles 2(20) = 40°
3x = 3(20) = 60°
6x = 6(20) = 120°
7x = 7(20) = 140°
Posted by દેવાયત ભેટારીયા 6 years, 11 months ago
- 1 answers
Posted by Albarr Ahmad 6 years, 11 months ago
- 2 answers
Posted by Zaid Hasan 6 years, 11 months ago
- 2 answers
Ram Kushwah 6 years, 11 months ago
3x-2y=5-----------------------(1)
-2x +3y=3--------------------(2)
Adding (1) and (2) we get
3x-2x-2y+3y=5+3
or x+y=8
Yogita Ingle 6 years, 11 months ago
3x - 2y = 5 ...... (i)
3y - 2x = 3
-2x + 3y = 3 ........ (ii)
Add (i) and (ii)
3x - 2y = 5
-2x + 3y = 3
___________
x + y = 8
Posted by Nitin Koshle 6 years, 11 months ago
- 0 answers
Posted by Pawan Pandey 6 years, 11 months ago
- 4 answers
Posted by Ashwani Kumar 6 years, 11 months ago
- 6 answers
Posted by Sahil Choudhary 6 years, 11 months ago
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Posted by Finaz Ahamed 6 years, 11 months ago
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Posted by Harsh Thakur 6 years, 11 months ago
- 4 answers
Posted by Utkarsh Kumar 6 years, 11 months ago
- 2 answers
Posted by Dev M Deva. 6 years, 11 months ago
- 3 answers
Posted by Satish Joshi 6 years, 11 months ago
- 1 answers
Jaskirat Singh 6 years, 11 months ago
Posted by Karan Shah 6 years, 11 months ago
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Sahil Pawar 6 years, 10 months ago
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