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Let's take shriya's present age as x and Arjun's age be 2x yrs. Shriya's age 5yrs. Ago was x-5 Arjun's age 5yrs. Ago was 2x-5 so , 2x-5 = 3(x-5) , 2x-5=3x-15 ,15-5= 3x-2x ,10 =x

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Sneha Ramparia 5 years, 6 months ago

Let Shriya present age = x years Let arjuns present age = 2x years Five years ago, Shriya's age=(x-5)years Arjuns's age=(2x-5)years Given, Five years ago arjun's age=3×Five years ago Shriya's age A.T.Q 2x-5=3(x-5) 2x-5=3x-15 2x-3x=-15+5 -x=-10 x=10 Arjun's age=2x=2×10=30

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Hamza Juned 5 years, 6 months ago

30,,?

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Solution of 3(x+2)=2x+3

Posted by Legendary Gaming 5 years, 6 months ago

CBSE > Class 08 > Mathematics

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Sneha Ramparia 5 years, 6 months ago

3x+6=2x+3 3x-2x=-6+3 x=-3

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When two parallel lines are cut by transversal , how many pass of angles so formed? List out and write there properties

Posted by Diya S Deepak 5 years, 6 months ago

CBSE > Class 08 > Mathematics

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Sneha Ramparia 5 years, 6 months ago

Each of the parallel lines cut by the transversal has 4 angles surrounding the intersection. These are matched in measure and position with a counterpart at the other parallel line. At each of the parallel lines, there are two pairs of vertical angle. Each angle in the pair is congruent to the other angle in the pair. 1 4, angle 1 is congruent to angle 4. 2 3, angle 2 is congruent to angle 3. 5 8, angle 5 is congruent to angle 8. 6 7, angle 6 is congruent to angle 7. Adjacent Supplementary Angles At each of the parallel lines adjacent angles are supplementary. Names for the Matched Angles The angles have special names identifying their positions with respect to the parallel lines and transversal. They are corresponding angles, alternate interior angles, or alternate exterior angles. An angles is congruent to its matched angle.

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3 ki power 0 + 4 ki power minus 1 x 2 ki power 2

Posted by Anuvadika Agrawal 5 years, 6 months ago

CBSE > Class 08 > Mathematics

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(-2)^-3×(-3)^×-3(-4)^×-3

Posted by Ankit Jha 5 years, 6 months ago

CBSE > Class 08 > Mathematics

1 answers

Sneha Ramparia 5 years, 6 months ago

2 {x-3 (x-5)}=6-5x -2 {x-3x+15}=6-5x -2 {-2x+15}=6-5x 4x-30=6-5x 4x+5x=30+6 9x=36 x=4

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(-2)^3×(-3)^-3×(-4)^-3

Posted by Ankit Jha 5 years, 6 months ago

CBSE > Class 08 > Mathematics

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X/2-1/5=x/3+1/4

Posted by Kundati Manjare 5 years, 6 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 6 months ago

x/2-1/5=x/3+1/4

x/2 -x/3= 1/4 + 1/5

(3x-2x)/6 = 9/20

x/6= 9/20

20x = 54

x = 54/20

x = 27/10

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Solve 6x+1/3+1=x-3/6

Posted by Prince Sahani 5 years, 6 months ago

CBSE > Class 08 > Mathematics

2 answers

Prince Sahani 5 years, 6 months ago

Thanks

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Yogita Ingle 5 years, 6 months ago

6x+1/3+1=x-3/6

6(6x + 1) = 4(x-3)

36 x + 6= 4x - 12

36x - 4x = -12 -6

32x = - 18

x= -18/32

x= - 9/16

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What should be added to twice the rational number -7/3 to get 3/7?

Posted by Prince Sahani 5 years, 6 months ago

CBSE > Class 08 > Mathematics

1 answers

Sneha Ramparia 5 years, 6 months ago

Let the number added be x Twice the rational number = 2×-7/3=-14/3 A.T.Q x + -14/3 = 3/7 x=14/3+3/7 (L.C.M=21) x=14/3=98/21 3/7=9/21 x=98+8/21 =107/21 =5 2/21

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The sum of three consecutive multiples of 11 is 363. Find these multiples.

Posted by Prince Sahani 5 years, 6 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 6 months ago

Let us take the first number as 11 (x – 1)

First consecutive number that is a multiple of 11 is 11x

Second consecutive number that is a multiple of 11 is 11(x + 1)

Therefore, the sum of 3 multiple of 11 numbers is 11x + 11(x – 1) + 11(x + 1) = 363

Now the sum of 3 numbers are 11x + 11(x – 1) + 11(x + 1) = 363

33x = 363; x = 33,

By substituting x = 33 in numbers 11x, 11(x – 1) and 11(x + 1) we get values 110, 121, 132.

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Present ages of Anu and Raj are in the ratio 4:5. Eight years from now the ratio of their ages will be 5:6. Find their present ages.

Posted by Prince Sahani 5 years, 6 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 6 months ago

Let ages if them be 4x and 5x
according to Question:
4x+8+5x+8 = 5x+6x
9x+16=11x
11x-9x=16
2x=16
x=16/2
x=8
present age of anu = 4x = 4 × 8 = 32
present age of raj = 5x = 5 ×8 = 40

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ANSWER

Arjun is twice as old as shriya. Five years ago his age was three times as old as shriya.

Posted by Prince Sahani 5 years, 6 months ago

CBSE > Class 08 > Mathematics