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Ask QuestionPosted by Tanupreet Kaur 5 years, 4 months ago
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Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
A n s w e r :
To Factorise : m2 + 3m − 4
By splitting the middle term
= m2 − 4m − m − 4
= m (m + 4) −1(m + 4)
= (m−1) (m+4)
So, m2 + 3m − 4 = (m−1) (m+4)
Posted by Kandula Mohan . Sai Pranav 5 years, 4 months ago
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Posted by Manas Nerkar 5 years, 4 months ago
- 2 answers
Yogita Ingle 5 years, 4 months ago
The constant of variation in a direct variation is the constant (unchanged) ratio of two variable quantities.
The formula for direct variation is
y=kx (or y=kx )
where kk is the constant of variation .
The constant of variation in an indirect variation is the constant (unchanged) product between two variable quantities.
The formula for indirect variation is
xy=kx (or y=k/x )
where kk is the constant of variation .
Posted by Kalp Shah 5 years, 4 months ago
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Posted by Tanupreet Kaur 5 years, 4 months ago
- 2 answers
Rahul Gupta 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
To Factorise : x2+2x−15
By splitting the middle term
=x2+5x−3x−15
=x(x+5)−3(x+5)
=(x−3)(x+5)
So, x2+2x−15=(x−3)(x+5)
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
p2+5p+6
By splitting the middle term →
= p2+3p+2p+6
=p(p+3)+2(p+3)
=(p+2)(p+3)
So, p2+5p+6=(p+2)(p+3)
Posted by Aman Khan 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
(a + b)3 = (a + b)(a + b)(a + b)
Multiply (a + b) and (a + b).
(a + b)3 = (a2 + ab + ab + b2)(a + b)
Simplify.
(a + b)3 = (a2 + 2ab + b2)(a + b)
(a + b)3 = a3 + a2b + 2a2b + 2ab2 + ab2 + b3
Combine the like terms.
(a + b)3 = a3 + 3a2b + 3ab2 + b3
or
(a + b)3 = a3 + b3 + 3ab(a + b)
Posted by Reshmika Reshmika 5 years, 4 months ago
- 1 answers
Posted by Surbhi Srishti 5 years, 4 months ago
- 0 answers
Posted by Mano Mallan 5 years, 4 months ago
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Posted by <Vansh> Rawat© 5 years, 4 months ago
- 3 answers
Yogita Ingle 5 years, 4 months ago
The number of heptagon sides = 7
Since all the sides “a” of a regular heptagon are of equal measure, then the perimeter or circumference of a heptagon is written as,
The perimeter of a heptagon, P = 7a units
Posted by Rahul Chaurasiya 5 years, 4 months ago
- 1 answers
Kalp Shah 5 years, 4 months ago
Posted by Sufian Choudhary 5 years, 4 months ago
- 0 answers
Posted by Tanupreet Kaur 5 years, 4 months ago
- 3 answers
Manthan Khedekar 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
p4 – (p + q)4
= (p2)2 – [(p + q)2]2
=[p2 - (p+q)2][p2 + (p+q)2]
= {[p -(p+q)][p +(p+q)]}[p2 + p2 + q2 + 2pq]
= {[p -p- q)][p +p+q]}[2p2 + q2 + 2pq]
= { - q)[2p+q]}[2p2 + q2 + 2pq]
Posted by Sri Magathi 5 years, 4 months ago
- 3 answers
Yogita Ingle 5 years, 4 months ago
505050 is not a perfect square because its unit's place digit is 0.
Posted by Kasiviswanadham Ravipati 5 years, 4 months ago
- 1 answers
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
x2 - y2 - 9 z2 + 6 y z
x2 - y2 - (3 z) 2 + 2 (y) (3 z)
x2 - (y - 3 z) ^2
a^2 - b^2 = a + b (a-b)
(x - y + 3 z ) (x + y - 3 z)
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Factorization of the expression is
Given:
To Find:
Factorization of
Solution:
The given expression is,
Now, the above expression can be written as
The above expression can be written as,
Now, we get
Now, on expanding the above equation, the new expression is,
Now, the equation becomes,
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Zibiah Gonsalves 5 years, 4 months ago
Posted by Tanupreet Kaur 5 years, 4 months ago
- 2 answers
Kasiviswanadham Ravipati 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
The given expression is,
Now, the above expression can be written as
The above expression can be written as,
Now, we get
Now, on expanding the above equation, the new expression is,
Now, the equation becomes,
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
10 a² - 20 ab² + 10 b⁴
= 10 a² - 10ab² - 10ab² + 10b⁴
= 10a( a - b²) - 10b² ( a - b²)
= (10a - 10 b²) ( a - b²)
Posted by Tanupreet Kaur 5 years, 4 months ago
- 4 answers
Isha ? 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
m4 -18m²n²+81n4
=(m2)2-18m²n²+(9n2)2
( a- b)2 = a2 - 2ab + b2
So, (m2)2-18m²n²+(9n2)2 = (m2 - 9n2)2
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
( a+ b)2 = a2 + 2ab + b2
36x²+84x +49 = (6x)²+2(6x)(7) +(7)2
= (6x + 7)2
Posted by Akash Kumar 5 years, 4 months ago
- 2 answers
Jubraj Jani 5 years, 4 months ago
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Yogita Ingle 5 years, 4 months ago
{tex}49a^6 - 28a^3b^3 + 4b^6{/tex}
{tex}= (7a^3)^2 - 2(7a^3)(2b^3) + (2b^3)^2 ... (looks like (a-b)^2 = a^2 - 2ab + b^2){/tex}
{tex}= (7a^3 - 2b^3)^2{/tex}
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Zibiah Gonsalves 5 years, 4 months ago
Posted by G P 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Construct a quadrilateral ABCD in which AB= 4.2cm, BC= 6cm, CD=5.2cm, DA=5cm and AC= 8 cm.
The given Quadrilateral ABCD can be drawn by following the steps.
Step1: Draw a line AB= 4.2cm
Step2: With A as the centre and radius = 8cm draw an arc.
Step3: with B as the centre and radius = 6cm draw another arc cutting previous arc. Label this point as C
Step4: Join BC
Step5: With A as the centre and radius = 5cm draw an arc.
Step6: with C as the centre and radius = 5.2cm draw another arc cutting previous arc. label this point as D
Step7: join CD and AD.
∴ The constructed quadrilateral looks like:
Posted by Tanupreet Kaur 5 years, 4 months ago
- 1 answers
Zibiah Gonsalves 5 years, 4 months ago
Posted by Tanupreet Kaur 5 years, 4 months ago
- 2 answers
Yogita Ingle 5 years, 4 months ago
1+ 2p +p²
= 1 + p + p + p2
= 1 ( 1+ p) + p (1 + p)
= ( 1 + p) ( 1 + p)
= ( 1 + p)2
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Gaurav Seth 5 years, 4 months ago
Answer:
1Thank You