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Sia ? 3 years, 1 month ago
Here, {tex}\frac {3}{13} \div \frac {-4}{65}{/tex}
= {tex}\frac {3}{13} \times \frac {65}{-4}{/tex}
= {tex}\frac {65 \times 3}{13 \times (-4)}{/tex}
= {tex}\frac {15}{-4}{/tex}
Therefore, the reciprocal is {tex}\frac {-4}{15}{/tex}
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Sia ? 3 years, 1 month ago
If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent. The "included angle" in SAS is the angle formed by the two sides of the triangle being used. The "included side" in ASA is the side between the angles being used.
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Sia ? 3 years, 1 month ago
Given: Area of parallelogram=1470 cm2
Base(AB)=35 cm and base(AD)=49 cm
Since, Area of parallelogram=base×height
⇒1470=35×DL
⇒ DL=1470/35
⇒ DL=42 cm
Again, Area of parallelogram=base×height
⇒1470=49×BM
⇒BM=1470/49
⇒BM=30 cm
Thus, the lengths of DL and BM are 42 cm and 30 cm respectively.
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Sanskar Pardeshi 3 years, 1 month ago
1Thank You