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Sh ~?Shrawni 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
2x - y = 6
Put x = 2 and y = -2
LHS = = 2x - y
= 2(2) - (-2)
= 4 + 2
= 6
= RHS
So, (2,-2) is a solution of 2x - y = 6.
Posted by Sandhya Pathak 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
We know that a quadratic polynomial when the sum and product of its zeroes are given by
p(x) = K {x2 – (sum of the zeroes) x + Product of zeroes},
where K is a constant.
Therefore, required quadratic polynomial p(x) is given by
p(x) = K[x2–(5x)+(6)] = K (x2 - 5x+ 6).
Posted by Shivam Mishra 6 years, 10 months ago
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Nilesh Is Here 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
Perimeter of semicircle = 1/2 (2π r) = πr
Area of semicircle = 1/2 πr2
So, perimeter and area of semicircle are equal.
Posted by Gurpal Singh 6 years, 10 months ago
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Ram Kushwah 6 years, 10 months ago
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Mehul, Barnwal 6 years, 10 months ago
Ram Kushwah 6 years, 10 months ago

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Izmam Husain 6 years, 10 months ago
3Thank You