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Preeti Dabral 1 year, 8 months ago
To find a triangle's area, use the formula area = 1/2 * base * height. Choose a side to use for the base, and find the height of the triangle from that base. Then, plug in the measurements you have for the base and height into the formula.
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Posted by Sakshi Singh 1 year, 8 months ago
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Preeti Dabral 1 year, 8 months ago
P = Rs. 1800
R = 8% per annum
{tex} = \frac{1}{4} \times 8\% {/tex} quarterly
= 2% quarterly
n = 1 year
= 4 quarters
{tex}\therefore A = P{\left( {1 + \frac{R}{{100}}} \right)^n}{/tex}
{tex} = 1800{\left( {1 + \frac{2}{{100}}} \right)^4}{/tex}
{tex} = 1800{\left( {1 + \frac{1}{{50}}} \right)^4}{/tex}
{tex} = 1800{\left( {\frac{{51}}{{50}}} \right)^4}{/tex}
{tex} = 1800 \times \frac{{51}}{{50}} \times \frac{{51}}{{50}} \times \frac{{51}}{{50}} \times \frac{{51}}{{50}}{/tex}
= Rs. 1948.38.
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Preeti Dabral 1 year, 8 months ago
S.P. = C.P. – Loss
{tex}\therefore{/tex} 13500 = C.P. – 20% of C.P.
{tex}\therefore{/tex} 13500 = C.P. – {tex}\frac{20}{100} \times{/tex} C.P.
{tex}\therefore{/tex} 13500 = C.P. – {tex}\frac{1}{5} \times{/tex} C.P.
{tex}\therefore{/tex} 13500 = {tex}\left(1-\frac{1}{5}\right){/tex} C.P.
{tex}\therefore{/tex} 13500 = {tex}\frac{4}{5}{/tex} C.P.
{tex}\therefore{/tex} C.P. = {tex}\frac{13500 \times 5}{4}{/tex}
{tex}\therefore{/tex} C.P. = 16875
Hence, she bought it at price Rs. 16875.
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Mohit Mohit 1 year, 8 months ago
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Preeti Dabral 1 year, 8 months ago
1. Draw a line A B.
2. On line, A B take point Q and point P outside A B.
3. Join the points P Q.
4. Take Q as a center and draw an arc to cut A B at E and P Q at F.
5. Take \mathrm{P} as a center and draw an arc to cut Q P at G.
6. Take G as the center has a radius equal to E F, and draw an arc to cut the previous arc at H.
7. Join the line P H and produce it on both sides to attain the required line C D.
8. The required diagram is,
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Gaurvi Sharma 1 year, 7 months ago
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