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Shubh Kumar Singh 1 year, 8 months ago
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Preeti Dabral 1 year, 8 months ago
{tex}\begin{aligned} & \mathrm{A}_1=100 \mathrm{~A}_2 \\ & \Rightarrow \frac{\mathrm{A}_1}{\mathrm{~A}_2}=100 \\ & \Rightarrow \frac{\pi \mathrm{r}_1^2}{\pi \mathrm{r}_2^2}=100 \end{aligned}{/tex}
{tex}\begin{aligned} & \Rightarrow \frac{\mathrm{r}_1}{\mathrm{r}_2}=10 \\ & \text { So, } \frac{\mathrm{c}_1}{\mathrm{c}_2}=\frac{2 \pi \mathrm{r}_1}{2 \pi \mathrm{r}_2} \\ & =\frac{\mathrm{r}_1}{\mathrm{r}_2}=\frac{10}{1} \end{aligned}{/tex}
Posted by Srini Vasan 1 year, 8 months ago
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Posted by Ayush Gautam 1 year, 8 months ago
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Preeti Dabral 1 year, 8 months ago
Let the total no. of teachers in the school be 'x'
Then, total no. of male teachers= 3x/4
Total no. of female teachers= x/4
=> Required ratio= (3x/4)*(4/x)= 3/1= 3:1.
Posted by Palak Nimade 1 year, 8 months ago
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Posted by Tharani Tharani 1 year, 8 months ago
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Preeti Dabral 1 year, 8 months ago
Given the ratio of the ages of two students = 5 : 3
Let their ages be 5<m:omath><m:r>x</m:r></m:omath> and 3<m:omath><m:r>x</m:r></m:omath>
After 6 years, their ages will be 5<m:omath><m:r>x</m:r></m:omath> + 6 and 3<m:omath><m:r>x</m:r></m:omath> + 6
Ratio of their ages after 6 years = 7 : 5
According to the question:
5<m:omath><m:r>x</m:r></m:omath> + 6 : 3<m:omath><m:r>x</m:r></m:omath> + 6 = 7 : 5
Product of mean = Product of extreme
⇒ 5(5<m:omath><m:r>x</m:r></m:omath> + 6) = 7 (3<m:omath><m:r>x</m:r></m:omath> + 6)
⇒ 25<m:omath><m:r>x</m:r></m:omath> + 30 = 21<m:omath><m:r>x</m:r></m:omath> + 42
⇒ 25<m:omath><m:r>x</m:r></m:omath> - 21<m:omath><m:r>x</m:r></m:omath> = 42 – 30
⇒ 4<m:omath><m:r>x</m:r></m:omath> = 8<m:omath><m:r>
⇒ x</m:r></m:omath> = 2
Hence the present ages of two students are 5(2) = 10 years and 3(2) = 6 years.
Rohit Yadav 1 year, 8 months ago
Posted by D Pavan Kumar 1 year, 8 months ago
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Akshara Kulkarni 1 year, 8 months ago
Rohit Yadav 1 year, 8 months ago
Posted by Ayush Gautam 1 year, 8 months ago
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Preeti Dabral 1 year, 8 months ago
Step-by-step explanation:
37-[5+{28-(19-7)}]
=37-[5+{28-(12)}]
=37-[5+{28-12}]
=37-[5+{16}]
=37-[5+16]
=37-[21]
=37-21
=16
Akshara Kulkarni 1 year, 8 months ago
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Akshara Kulkarni 1 year, 8 months ago
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Gaurvi Sharma 1 year, 7 months ago
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