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Yogita Ingle 6 years ago
Given: l= 30cm, b= 24cm, h= 18cm
To find the maximum length of the rod We have to find its diagonal.
Length of a diagonal of a cuboidal box is=√l²+b²+h²
= √(30)²+(24)²+(18)²= √900+576+324
= √1800 = √100×9 × 2= 30√2
= 30×1.41 = 42.3cm (√2= 1.41)
The maximum length of the rod is 42.3cm
Posted by Rahul Kumar 6 years ago
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Arifa Rahman 6 years ago
Yogita Ingle 6 years ago
The Circumference (or) perimeter of a circle = 2πR
where,
R is the radius of the circle
π is the mathematical constant with an approximate (up to two decimal points) value of 3.14
Again,
Pi (π) is a special mathematical constant, it is the ratio of circumference to diameter of any circle.
where C = π D
C is the circumference of the circle
D is the diameter of the circle
Posted by Bhanu Sahu 6 years ago
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Gaurav Seth 6 years ago
Pythagoras Theorem. (B audhayan Theorem)
Theorem 8.3: - In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Given: - 
is a right angle of 
To Prove:-
Construction:-
is drawn
Proof:- In
Or, AB2 = AC X AD ---------------------(i)
Similarly
Or, BC2 = AC X CD ---------------------(ii)
Adding (i) and (ii) we get
AB2 + BC2 = AC X AD + AC X CD
= AC X (AD + CD)
= AC X AC
= AC2
Or, AC2 = AB2 + BC2
Posted by Santhosh Reddy 6 years ago
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Yogita Ingle 6 years ago
Given side of the square park = 66 m
Hence area of square park = side × side
= 66× 66 = 4356 sq m
Given length of rectangular park, l = 90 m
Let the breadth of the rectangular park be "b"
Area of rectangular park = l × b
But given area of rectangular park = area of square park
⇒ 90 × b =4356
⇒ b = 4356/90 = 48.4
Hence breadth of the rectangular park is 48.4 m.
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Any Khan 6 years ago
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