No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Yogita Ingle 5 years, 11 months ago

Perimeter of square = 4 × side
26 = 4 × side

➡ side = 26/4

➡ side = 6•5 cm

Area of square = side × side

➡ 121 = side²

➡ side = √121

➡ side = 11 cm.

Ratio of the length of two squares =

➡ 6•5 : 11 = 13 : 22

 

  • 1 answers

.. ... 5 years, 11 months ago

Pythagorean Theorem is one of the most fundamental theorems in mathematics and it defines the relationship between the three sides of a right-angled triangle. You are already aware of the definition and properties of a right-angled triangle. It is the triangle with one of its angles as a right angle, that is, 90 degrees. The side that is opposite to the 90-degree angle is known as the hypotenuse. The other two sides that are adjacent to the right angle are called legs of the triangle. Formula a^2 + b^2 = c^2 a = side of right triangle b = side of right triangle c = hypotenuse
  • 1 answers

.. ... 5 years, 11 months ago

Terms :- y,y Coefficient of y2:-x
  • 0 answers
  • 2 answers

Aabha Singh 5 years, 11 months ago

3

Madhav Gautam 5 years, 11 months ago

135
  • 0 answers
  • 2 answers

Yuga Pendor 5 years, 11 months ago

Circumferemce=πd =3.14×1.5{π=3.14} =4.710m. Cost of 1 m. lace=₹15 Cost of 4 .710m. lace = 4.710×15 = ₹ 70.650

Any Khan 5 years, 11 months ago

Find the circumference of cirlcle and then multiply the answer with 15
  • 0 answers
  • 2 answers

Aparna Tiwari 5 years, 11 months ago

1234

Meenu Chaudhary 5 years, 11 months ago

11765
  • 1 answers

Meenu Chaudhary 5 years, 11 months ago

11765
  • 1 answers

.. ... 5 years, 11 months ago

A=πr2=π·122≈452.38934
5*6
  • 2 answers

Ayush Gupta 5 years, 11 months ago

30

Nirmala Kachapur 5 years, 11 months ago

30
  • 1 answers

.. ... 5 years, 11 months ago

C2
  • 1 answers

Aparna Tiwari 5 years, 11 months ago

Color part is numerator and color part without colour add is denominator
  • 1 answers

Yogita Ingle 5 years, 11 months ago

The perimeter of the semi circular park is {tex}P=2r+\pi r{/tex}

We have given, P=72

{tex}P=r(2+\pi){/tex}

{tex}72=r(2+3.14){/tex}

{tex}72=r(5.14){/tex}

{tex}r=\frac{72}{5.14}{/tex}

r=14

The radius of the semi circular park is 14 meter.

The area of the semi circular park is {tex}A=\frac{\pi r^2}{2}{/tex}

{tex}A=\frac{3.14\times 14^2}{2}{/tex}

{tex}A=\frac{3.14\times 196}{2}{/tex}

{tex}A=3.14\times98{/tex}

{tex}A=307.72m^2{/tex}

Therefore, The area of the semi circular park is 307.72 square meter.

 

  • 0 answers
  • 2 answers

Neha Mondal 5 years, 11 months ago

Thanks yogita

Yogita Ingle 5 years, 11 months ago

Radius of pipe = 18 cm.

If we wrap ... then it means that we cover the circumference...

So circumference = 2πr
= 2 × 3.14 × 28
= 56  × 3.14
= 175.84 cm.

But according to the question....

The tape is to be wrapped twice.....
so...

= 2 × 175.84
= 351.68 cm.

Hence the length of tape required is 351.68 cm.

 

  • 0 answers
  • 0 answers
  • 0 answers
  • 0 answers
  • 1 answers

Fiyyaz Khan 5 years, 11 months ago

Pathri metre wide track Run outside a rectangular Park of length 10 M and 80 m find the area of track also find the cost of cementing the track @ rupees 95 per square metre
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App