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Yogita Ingle 5 years, 11 months ago
The perimeter of the semi circular park is {tex}P=2r+\pi r{/tex}
We have given, P=72
{tex}P=r(2+\pi){/tex}
{tex}72=r(2+3.14){/tex}
{tex}72=r(5.14){/tex}
{tex}r=\frac{72}{5.14}{/tex}
r=14
The radius of the semi circular park is 14 meter.
The area of the semi circular park is {tex}A=\frac{\pi r^2}{2}{/tex}
{tex}A=\frac{3.14\times 14^2}{2}{/tex}
{tex}A=\frac{3.14\times 196}{2}{/tex}
{tex}A=3.14\times98{/tex}
{tex}A=307.72m^2{/tex}
Therefore, The area of the semi circular park is 307.72 square meter.
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Yogita Ingle 5 years, 11 months ago
Radius of pipe = 18 cm.
If we wrap ... then it means that we cover the circumference...
So circumference = 2πr
= 2 × 3.14 × 28
= 56 × 3.14
= 175.84 cm.
But according to the question....
The tape is to be wrapped twice.....
so...
= 2 × 175.84
= 351.68 cm.
Hence the length of tape required is 351.68 cm.
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Yogita Ingle 5 years, 11 months ago
Perimeter of square = 4 × side
26 = 4 × side
➡ side = 26/4
➡ side = 6•5 cm
Area of square = side × side
➡ 121 = side²
➡ side = √121
➡ side = 11 cm.
Ratio of the length of two squares =
➡ 6•5 : 11 = 13 : 22
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