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A particle is moving in a straight line such that it's velocity is increasing at 5m/s per meter.the acceleration of the particle is_meter per second square at a point where it's velocity is 20 meter per second

Posted by Ashish Ranjan Kr.Priye 6 months, 2 weeks ago

Entrance Exam > JEE Advanced > Physics

2 answers

Aditya Bhatt 5 months, 3 weeks ago

When the velocity of particle is 20 m/s then Distance travelled in 1 second = 20m Distance travelled in 1/20 second = 1m After covering 1m distance the velocity of particle become 25 m/s. It means, in 1/20 second, the velocity of particle increased by 5m/s. Thus acceleration a = ∆v/∆t = 5/(1/20) = 5×20 = 100 m/s²

4Thank You

Ankit Singh 6 months, 1 week ago

a=(v-u)/t = 25-20/1 = 5 m/ s^2

3Thank You

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Posted by Pappu Kumar Mahto 1 month ago

Entrance Exam > JEE Advanced > Physics