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Calculate the number of electrons present …

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Calculate the number of electrons present in 9.5gm of phosphate ion

    • Posted by Alina Patnaik 2 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 2 years, 1 month ago

    No of moles = 9.5 / 95 = 0.1 mol. No of ions = 0.1 × 6.022 × 10^23 = 6.022 × 10^22 ions. (NOW, 1 (PO4)3- HAS 15 + 32 + 3 = 50e) Therefore, no of el = 50 × 6.022 × 10^23 = 3.011 × 10^25 electrons //

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