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1. An athlete completes one round …

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1. An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?
  • 3 answers

Sumit Kumar 1 year, 4 months ago

Bro it also can done by using 2πr first 6 1/2 rounds is eqal to 140 sec πr2x1/200 we get r = 100 take common from (2xπr)(πr) common is =πr. And 6 1/2 is now eqal to 7 Now put only πr from common 7x22/7x100 = 2200 And the displacement is eqal to =0 Because only half of circle is coverd

Sumit Kumar 1 year, 4 months ago

Bro it also can done by using 2πr first 6 1/2 rounds is eqal to 140 sec πr2x1/200 we get r = 100 take common from (2xπr)(πr) common is =πr And now put 2πr 2x22/7x100 =2200m And the displacement is eqal to =0 Because only half of circle is coverd

Kapil Kumar 1 year, 5 months ago

1min = 60sec 2min = 120sec + 20sec = 140sec Circumference = 200m Time taken for 1 round = 40s A.T.Q, 1 ROUND = 40sec 2 ROUND = (40+40)sec =80 sec 3 ROUND = (40+40+40)sec = 120 sec {140sec - 120sec = 20sec} 1/2 ROUND = 20 sec So,,,,, *DISTANCE* (1+2+3+1/2) round =200+200+200+200/2 =200+200+200+100 =700m Then,,,,, Displacement u = 0 v = 100 So displacement will be 100 m as he travelled 3.5 rounds so for 3 rounds displacement will be zero but for the half round displacement will be 100m Thanks 🙏
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