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Engine of a train exerts a force of 6000 N. If total mass of the train and the engine be 18000kg, and initially the train was standing on the platform, what is the magnitude of velocity attained by the train 20s after the start? Assume that there is no frictional force between the railway track and the train and motion is in a horizontal direction.

Posted by Aryan Jain 1 year, 8 months ago

CBSE > Class 09 > Science

2 answers

Rohit Luna 1 year, 7 months ago

F=MA THEN, 6000=18000×A, A=6000/18000, A=0.3 m/s² THEN, WE HAVE FIND THE FINAL VELOCITY BY FIRST EQUATION OF MOTION V=U+AT V=0+0.3×20 V=6m/s

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Aryan Jain 1 year, 8 months ago

Please answer me for this question

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