9. If A = [[- i, …

Hmm' got it 👍 thanks

Solution We can calculate the product AB as follows: AB = [[-i, 0], [0, i]] [[1, 0], [0, -1]] = [[-i, 0], [0, -i]] Next, we can calculate the determinant of AB as follows: det(AB) = (-i) * (-i) - 0 * 0 (determinant of a 2x2 matrix) = 1 Now, we can use the formula for the product of determinants to find the determinant of A multiplied by the determinant of (i^2-1)B: det(A) * det((i^2-1)B) = det(AB) det(A) * (i^2-1)^2 * det(B) = 1 Substituting the known values, we get: det(A) * (i^2-1)^2 * (-1/1) = 1 det(A) * 4 = 1 det(A) = 1/4 Since A is a 2x2 matrix, its determinant can be calculated as follows: det(A) = (-i) * i - 0 * 0 (determinant of a 2x2 matrix) = -1 Therefore, we have a contradiction: det(A) = -1 and det(A) = 1/4. Hence, there is no value of a that satisfies the given conditions.