Four times the area of curb …

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Preeti Dabral 2 years, 8 months ago
Let the radius and height of the cylinder be r and h, respectively.
Curved surface area of cylinder = 2{tex}\pi{/tex}rh
Area of base = {tex}\pi{/tex}r2
Sum of areas of bases = 2{tex}\pi{/tex}r2
According to the question, 4 {tex}\times{/tex} Curved surface area = 6 {tex}\times{/tex} Sum of areas of bases
4 {tex}\times{/tex} 2{tex}\pi{/tex}rh = 6 {tex}\times{/tex} 2{tex}\pi{/tex}r2
= 8{tex}\pi{/tex}rh = 12{tex}\pi{/tex}r2
= 2h = 3r
{tex}\Rightarrow \quad r=\frac{2}{3} h{/tex}
{tex}\therefore \quad r=\frac{2}{3} \times 12{/tex} = 8cm [{tex}\because{/tex} h = 12 cm, given]
{tex}\therefore{/tex} Curved surface area of the cylinder = 2{tex}\pi{/tex}rh
= {tex}2 \times \frac{22}{7} \times 8 \times 12=\frac{44 \times 8 \times 12}{7}{/tex}
= 603.428 cm2
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