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a bodybuilding lifts a dumbbell of 10 kg raises it 2m above the ground. calculate the work done by him on lifting the weight

Posted by Kartik Choudhary 1 year, 9 months ago

CBSE > Class 09 > Science

5 answers

Sudhir Kumar 1 year, 9 months ago

0

Anshuman Mishra 1 year, 9 months ago

Work done = Change in P. E. =∆P.E. = mgh m =10 kg, g=9.8ms^-2, h=2 m W =10 ×9.8×2 = 98 ×2 = 196 J

Priyansu Kumar Sahoo 1 year, 9 months ago

Work done=Force* Displacement=Weight*Displacement=mgs =(10*9.8*2)J =196J

Shourya Verma 1 year, 9 months ago

196 joule

Priyansu Kumar Sahoo 1 year, 9 months ago

Work done is zero

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