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a bodybuilding lifts a dumbbell of 10 kg raises it 2m above the ground. calculate the work done by him on lifting the weight

Posted by Kartik Choudhary 1 year, 7 months ago

CBSE > Class 09 > Science

5 answers

Sudhir Kumar 1 year, 7 months ago

0

Anshuman Mishra 1 year, 7 months ago

Work done = Change in P. E. =∆P.E. = mgh m =10 kg, g=9.8ms^-2, h=2 m W =10 ×9.8×2 = 98 ×2 = 196 J

Priyansu Kumar Sahoo 1 year, 7 months ago

Work done=Force* Displacement=Weight*Displacement=mgs =(10*9.8*2)J =196J

Shourya Verma 1 year, 7 months ago

196 joule

Priyansu Kumar Sahoo 1 year, 7 months ago

Work done is zero

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CBSE > Class 09 > Science

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This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.

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Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
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