consider a body of mass m …

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consider a body of mass m falling freely from height h . if frictional force neglected then show that
1) At the maximum height, total energy is the potential energy.
2) At height h kinetic energy is equal to half of the total energy.
3) On touching the ground, total energy is equal to kinetic energy.
4) diving the motion of a body mechanical energy is conserved.
Posted by Savitajain Jain 8 years, 11 months ago
- 1 answers
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Shweta Gulati 8 years, 11 months ago
Suppose we have a ball of mass m and we raise it to a height h above the ground. The work done in raising the ball gives it a potential energy equal to m x g x h. So, at the maximum height, total energy is the potential energy.
Let us allow the ball to fall downwards. As the ball falls, its height h above the ground decreases and thus the potential energy also decreases. But as the ball falls, its velocity v constantly increases and, therefore, its kinetic energy mv2/2 also increases.
When the ball just reaches the ground, its potential energy becomes zero (h=0) and its kinetic energy becomes maximum.
There is no destruction of energy and the total amount of energy remains constant. This is an example of conservation of energy during the free fall of a body.
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