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25a2-4b2+28bc-49c2

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25a2-4b2+28bc-49c2
  • 2 answers

Yashika Sharma 3 years, 9 months ago

25a 2 −4b 2 −28bc−49c 2 =(5a) 2 −(2b) 2 +28bc−(7c) 2 =(5a) 2 −{(2b) 2 +2×2b×7c−(7c) 2 } ∵[(a+b) 2 =a 2 +b 2 +2ab] =(5a) 2 −(2b+7c) 2 ∵[a 2 −b 2 =(a−b)(a+b)] ={(5a)−(2b+7c)}{(5a)+(2b+7c)} =(5a−2b−7c)(5a+2b+7c)

Ayaan Deshmukh 3 years, 9 months ago

25a 2 −4b 2 −28bc−49c 2 =(5a) 2 −(2b) 2 +28bc−(7c) 2 =(5a) 2 −{(2b) 2 +2×2b×7c−(7c) 2 } ∵[(a+b) 2 =a 2 +b 2 +2ab] =(5a) 2 −(2b+7c) 2 ∵[a 2 −b 2 =(a−b)(a+b)] ={(5a)−(2b+7c)}{(5a)+(2b+7c)} =(5a−2b−7c)(5a+2b+7c)
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