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calculate the mass of sodium sulphate required to prepare its 20% ( mass percent ) solution in 100 g of water ?

Posted by Praveen Bhargav 3 years, 1 month ago

CBSE > Class 09 > Science

2 answers

Sia ? 3 years, 1 month ago

Let the mass of sodium sulphate required be 'x' g
The mass of water = 100 g
The mass of solution =(mass of sodium sulphate + mass of water) = (x + 100)g
Percentage of sodium sulphate in solution {tex}=\;\frac{Mass\;of\;sodium\;sulphate}{Mass\;of\;solution}\times100{/tex}
{tex}20=\frac{x}{x+100} \times 100{/tex}
20x + 2000 = 100x
80x = 2000
x = {tex}\frac{2000}{80}{/tex}
= 25 g
Therefore, the mass of sodium sulphate required is 25 g.

1Thank You

Praveen Bhargav 2 years, 10 months ago

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CBSE > Class 09 > Science