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A machinery worth rs10, 500 depreciated …

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A machinery worth rs10, 500 depreciated by 5%.find it's value after one year?

Posted by Barsha Rani Sahu 4 years, 2 months ago

CBSE > Class 08 > Mathematics

1 answers

Sia ? 4 years, 2 months ago

P = Rs. 10500
R = 5% per annum
h = 1 year
{tex}\therefore A = P{\left( {1 - \frac{R}{{100}}} \right)^n}{/tex}
{tex} = 10500{\left( {1 - \frac{5}{{100}}} \right)^1}{/tex}
{tex} = 10500\left( {1 - \frac{1}{{20}}} \right){/tex}
{tex} = 10500 \times \frac{{19}}{{20}}{/tex}
= 9975
Hence, value after 1 years is Rs. 9975

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