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If 2.36grm of sodium sulphate is …

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If 2.36grm of sodium sulphate is added to berium chloride the residue is formed to be 3.88grm of barium sulphate and 1.98grm of sodium chloride.What is the mass of barium chloride?

    • Posted by Deiba Pariong 3 years, 2 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Anjan Karthi 3 years, 2 months ago

    Law of conservation of mass. LHS = RHS. Therefore, 2.36g Na2SO4 + x g BeCl2 = 3.88g BaSO4 + 1.98g NaCl. Therefore, required mass of BeCl2 = 3.5 g. //

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