A rectangular tube of uniform cross …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sanshray Gupta 4 years, 8 months ago
- 1 answers
Test
Related Questions
Posted by Himanshi Sharma 1 year, 4 months ago
- 0 answers
Posted by Anmol Kumar 1 year, 4 months ago
- 0 answers
Posted by Moksh Bhatia 1 year, 4 months ago
- 0 answers
Posted by Huda Fatima 1 year, 4 months ago
- 2 answers
Posted by Prasanna Mendon 4 months, 4 weeks ago
- 1 answers
Posted by Op Garg 1 year, 4 months ago
- 2 answers
Posted by Yash Dwivedi 1 year, 4 months ago
- 3 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 4 years, 8 months ago
Q : A rectangular tube of uniform cross section has three liquids of densities ρ1, ρ2 and ρ3. Each liquid column has length l equal to length of sides of the equilateral triangle. Find the length x of the liquid density ρ1 in the horizontal limb of the tube, if the triangular tube is kept in the vertical plane.
Solution:
At junction force applied by left to coloumn = force applied by light of coloumn.
(1 − x) cos30o p1 gA + x cos30o p2 gA = (1 − x) cos30o p2 gA + x cos30o p3 gA
{tex}\Rightarrow{/tex} (1 − x)p1 + xp2 = (1 − x)p2 + xp3
{tex}\Rightarrow{/tex} p11 − p1x + xp2 = 1p2 − xp2 + p3x
{tex}\Rightarrow{/tex} xp2 − xp1 + xp2 − xp3 = 1p2 − 1p1
{tex}\Rightarrow{/tex} x(2p2 − p1 − p3) = 1(p2 − p1)
x = {tex}\frac {1(p_2 − p_1)}{2p_2 − p_1 − p_3}{/tex}
0Thank You