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a ball dropped from a height H. when it reached the ground, its velocity is 50m/s. what is its height

Posted by Akash As 3 years, 6 months ago

CBSE > Class 09 > Science

3 answers

Pata Monalisha 3 years, 6 months ago

Final velocity (V)=50m/s Acceleration = 10 Initial velocity =0 V^2-U^2=2as 50^2-0^2=2×10×s 2500=20s s=2500/20 s=125

Pata Monalisha 3 years, 6 months ago

Final velocity (V)=50m/s Acceleration = 10 Initial velocity =0 V^2-U^2=2as 50^2-0^2=2×10×s 2500=20s s=2500/20 s=125m

Pata Monalisha 3 years, 6 months ago

Final velocity (V)=50m/s Acceleration = 10 Initial velocity =0 V^2-U^2=2as 50^2-0^2=2×10×s 2500=20s s=2500/20 s=125m

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