An unlocked truck weighing 2000kg has …
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Sia ? 3 years, 5 months ago
1st case (unloaded truck)
m= 2000kg
a= 0.5 m/s2
F=m ×a
F= 2000×0.5 =1000N
2nd case (loaded truck)
m= 2000+2000= 4000kg
F=1000N (same) remain unchanged
F=m/a
a= F/m
a=1000/4000
a=0.25 m/s2
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