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1.Find square root of 100 and 169 by the method of repeated subtraction. 2.find the square root of the following numbers by the prime factorisation method (i) 9604 (ii) 7744 (iii) 8100 (iv) 400

Posted by Shaksham Gupta 4 years, 10 months ago

CBSE > Class 08 > Mathematics

4 answers

Vaishali M 4 years, 10 months ago

(¡) 9604= 22×72×72 9604=98 (¡¡) 7744= 22×22×22×112 7744=88 (¡¡¡) 8100=902 8100=90. (iv)400= 22×22×52 400=20

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Vaishali M 4 years, 10 months ago

Step 1: 169 - 1 =168 Step 2: 168 - 3 = 165 Step 3: 165 - 5 = 160 Step 4: 160 - 7 = 153 Step 5: 153 - 9 = 144 Step 6: 144 - 11 =133 Step 7: 133 - 13 =120 Step 8: 120 - 15 =105 Step 9: 105 - 17 =88 Step10: 88 - 19 = 69 Step 11: 69 - 21 = 48 Step 12: 48 - 23 = 25 Step 13: 25 - 25 = 0

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Vaishali M 4 years, 10 months ago

Step 1: 100 - 1 =99 Step 2: 99 - 3 = 96 Step 3: 96 - 5 = 91 Step 4: 91 - 7 = 84 Step 5: 84 - 9 = 75 Step 6: 75 - 11 =64 Step 7: 64 - 13 =51 Step 8: 51 - 15 =36 Step 9: 36 - 17 =19 Step10: 19 - 19 = 0

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Vaishali M 4 years, 10 months ago

Here, we will use the method of repeated subtraction i.e. .., subtracting successive odd numbers from the square. numbers from thesquare number, till you get zero. As, we got '0' in step10, the square root of 100 is 10 i.e..,√100=10.

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