The speed of bicycle decreases from …
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Posted by Rohan Sinha 4 years, 7 months ago
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Sia ? 4 years, 7 months ago
m = 70 kg
v = 9 kmph = 9 * 5/18 = 2.5 m/s
u = 18 kmph = 18 * 5/18 = 5 m/s
Work done = change in kinetic energy
= initial KE - final KE
= 1/2 m u² - 1/2 m v²
= 1/2 * 70 * 5² - 1/2 * 70 * 2.5²
= 875 J - 218.75 J = 656.25 J
The speed has come down to half its value. But the Kinetic energy becomes 218.75/875 = 1/4 th of inital KE.
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