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Molecular orbital theory for o2, n2 …

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Molecular orbital theory for o2, n2 ,f2
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Om P̤A̤T̤E̤L̤ 3 years, 9 months ago

Electronic configuration of nitrogen (Z = 7) is 1s2 2s2 2p3. Since nitrogen atom has 7 electrons, the molecular orbitals of nitrogen molecule (N2) has 14 electrons which are distributed as below : Molecular orbital energy level diagram of N2 molecule • Bond order =  (8 2)/2 = 3 (N ≡ N) • Absence of unpaired electrons showed that N2 molecule is diamagnetic. MOED of 'O2' : Electronic configuration of Oxygen (Z = 8) is 1s2 2s2 2p4 . Since Oxygen atom has 8 electrons, the molecular orbitals of Oxygen molecule (O2) has 16 electrons, which are distributed as below : Molecular orbital energy level diagram of O2 • Bond order = (10 - 6)/2 = 2(O = O) • Presence of two unpaired 6 electrons (π* 2p1y π*2p1z,) showed that O2 molecule is paramagnetic. Read more on Sarthaks.com - https://www.sarthaks.com/535006/give-the-molecular-orbital-energy-diagram-of-n2-and-o2-write-the-bond-order-of-n2-and-o2
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