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Draw the total possible isomers of …

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Draw the total possible isomers of C6H14.

    • Posted by Johal ? 3 years, 10 months ago

    CBSE > Class 11 > Chemistry
    • 2 answers

    Anuj Kumar 3 years, 10 months ago

    <cml><MDocument><MChemicalStruct><molecule molID="m1"><atomArray><atom id="a1" elementType="C" x2="-5.3125" y2="1.4322916666666667"/><atom id="a2" elementType="C" x2="-3.9788208781719643" y2="2.2022916666666665"/><atom id="a3" elementType="C" x2="-2.645141756343929" y2="1.4322916666666665"/><atom id="a4" elementType="C" x2="-1.311462634515<cml><MDocument><MChemicalStruct><molecule molID="m1"><atomArray><atom id="a1" elementType="C" x2="-5.3125" y2="1.4322916666666667"/><atom id="a2" elementType="C" x2="-3.9788208781719643" y2="2.2022916666666665"/><atom id="a3" elementType="C" x2="-2.645141756343929" y2="1.4322916666666665"/><atom id="a4" elementType="C" x2="-1.3114626345158946" y2="2.2022916666666665"/><atom id="a5" elementType="C" x2="0.022216487312141098" y2="1.4322916666666665"/><atom id="a6" elementType="C" x2="1.3558956091401768" y2="2.2022916666666665"/><atom id="a7" elementType="C" x2="-2.645141756343929" y2="-0.10770833333333352"/><atom id="a8" elementType="C" x2="-1.1504888010837082" y2="3.7338553855338077"/><atom id="a9" elementType="O" x2="-3.208820878171964" y2="3.5359707884947023" lonePair="2"/><atom id="a10" elementType="O" x2="-0.13875734612004503" y2="-0.09927205220047464" lonePair="2"/><atom id="a11" elementType="N" x2="2.895895609140177" y2="2.2022916666666665" lonePair="1"/><atom id="a12" elementType="C" x2="3.9263567429328186" y2="1.0578486354314793"/><atom id="a13" elementType="C" x2="3.371781780477596" y2="3.666918701761203"/><atom id="a14" elementType="C" x2="3.092652500649646" y2="-1.1867091514227464"/><atom id="a15" elementType="C" x2="3.997841789180055" y2="-2.4325953227601653"/></atomArray><bondArray><bond atomRefs2="a1 a2" order="1" id="b1"/><bond atomRefs2="a2 a3" order="1" id="b2"/><bond atomRefs2="a3 a4" order="1" id="b3"/><bond atomRefs2="a4 a5" order="1" id="b4"/><bond atomRefs2="a5 a6" order="1" id="b5"/><bond atomRefs2="a3 a7" order="1" id="b6"/><bond atomRefs2="a4 a8" order="1" id="b7"/><bond atomRefs2="a2 a9" order="1" id="b8"/><bond atomRefs2="a5 a10" order="1" id="b9"/><bond atomRefs2="a6 a11" order="1" id="b10"/><bond atomRefs2="a11 a12" order="1" id="b11"/><bond atomRefs2="a11 a13" order="1" id="b12"/><bond atomRefs2="a14 a15" order="1" id="b13"/></bondArray></molecule></MChemicalStruct><MElectronContainer occupation="0 0" radical="0" id="o1"><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o2"><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o3"><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o4"><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o5"><MElectron atomRefs="m1.a11" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a11" difLoc="0.0 0.0 0.0"/></MElectronContainer></MDocument></cml>8946" y2="2.2022916666666665"/><atom id="a5" elementType="C" x2="0.022216487312141098" y2="1.4322916666666665"/><atom id="a6" elementType="C" x2="1.3558956091401768" y2="2.2022916666666665"/><atom id="a7" elementType="C" x2="-2.645141756343929" y2="-0.10770833333333352"/><atom id="a8" elementType="C" x2="-1.1504888010837082" y2="3.7338553855338077"/><atom id="a9" elementType="O" x2="-3.208820878171964" y2="3.5359707884947023" lonePair="2"/><atom id="a10" elementType="O" x2="-0.13875734612004503" y2="-0.09927205220047464" lonePair="2"/><atom id="a11" elementType="N" x2="2.895895609140177" y2="2.2022916666666665" lonePair="1"/><atom id="a12" elementType="C" x2="3.9263567429328186" y2="1.0578486354314793"/><atom id="a13" elementType="C" x2="3.371781780477596" y2="3.666918701761203"/><atom id="a14" elementType="C" x2="3.092652500649646" y2="-1.1867091514227464"/><atom id="a15" elementType="C" x2="3.997841789180055" y2="-2.4325953227601653"/></atomArray><bondArray><bond atomRefs2="a1 a2" order="1" id="b1"/><bond atomRefs2="a2 a3" order="1" id="b2"/><bond atomRefs2="a3 a4" order="1" id="b3"/><bond atomRefs2="a4 a5" order="1" id="b4"/><bond atomRefs2="a5 a6" order="1" id="b5"/><bond atomRefs2="a3 a7" order="1" id="b6"/><bond atomRefs2="a4 a8" order="1" id="b7"/><bond atomRefs2="a2 a9" order="1" id="b8"/><bond atomRefs2="a5 a10" order="1" id="b9"/><bond atomRefs2="a6 a11" order="1" id="b10"/><bond atomRefs2="a11 a12" order="1" id="b11"/><bond atomRefs2="a11 a13" order="1" id="b12"/><bond atomRefs2="a14 a15" order="1" id="b13"/></bondArray></molecule></MChemicalStruct><MElectronContainer occupation="0 0" radical="0" id="o1"><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o2"><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a9" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o3"><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o4"><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a10" difLoc="0.0 0.0 0.0"/></MElectronContainer><MElectronContainer occupation="0 0" radical="0" id="o5"><MElectron atomRefs="m1.a11" difLoc="0.0 0.0 0.0"/><MElectron atomRefs="m1.a11" difLoc="0.0 0.0 0.0"/></MElectronContainer></MDocument></cml>

    2Thank You

    Royal Thakur ? 3 years, 10 months ago

    #Anubhav misra get out from here... Kyunki Ye app Tum jaise logo ke liye nhi h.....jha se Ye likhna sikhe Ho vha se Thodi respect Krna bhi sekh lete to Accha rehta.....dusro ke maa ke nhi to km se km apne maa ke respect kro Aur unke sanskaro ke bhi..... Same on you and also on people like you ??...Discusting you are ???

    8Thank You

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