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a farmer buys a plot of agricultural land for rs 4,50,000. he sells one third at the loss of 15% and two fifth at a gain of 20%. at what price he must sell his remaining land so as to make an overall profit at 10%?

Posted by Ramanpreet Kaur 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Mohd Talha 4 years, 11 months ago

CP = 3600000. To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000. 1/3 of the land sold on 20% loss. SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000. SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000. SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000. Second Method SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000. So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000. SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000. Hence, SP of the remaining field = Rs. (396000-96000-180000). = Rs. 120000.

0Thank You

Yogita Ingle 4 years, 11 months ago

First Method

CP = 3600000.

To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.

1/3 of the land sold on 20% loss.

SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.

SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.

SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.

Second Method

SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000.

So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.

SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.

Hence,

SP of the remaining field = Rs. (396000-96000-180000).

= Rs. 120000.

1Thank You

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