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A farmer moves along the boundary …

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A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

Posted by Jaynit Kumar 3 years, 9 months ago

CBSE > Class 09 > Science

1 answers

Gaurav Seth 3 years, 9 months ago

Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200

AC = (200)1/2

AC= 10× (2) ½ or 10√2 m

3Thank You

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