Describe Rutherford's Alpha Particle experiment
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Posted by Yash Aggarwal 3 years, 9 months ago
- 2 answers
Gaurav Seth 3 years, 9 months ago
In 1911 Rutherford made and experiment to study about the structure of atom. In this experiment the α-particles from 83Bi214 (a radioactive source) contained in a lead cavity are collinated into a narrow beam with the help of a lead plate having a narrow slit the narrow beam of α-particles then falls on a thin gold foil (about 2.1 x 10-10 m thick). The α-particles scattered in different directions.The whole apparatus was arranged inside a vaccum chamber toprevent the scattering of α-particles from air molecules. The experimental observations led Rutherford to the following conclusions-
(i) Since most of the α-particles passed undiviated, than atom has a lot of empty space in it.
(ii) Since the fast and the heavy α-particle could be deflected through even 180°, the whole of + ve charge and partcially the entire mass of the atom was confined to an extremely small central core.
It was called nucleus.
Since 1 in about 8000 α-particles in deflected through 180°, the size of the nucleus is about 1/10,000 th of the size of the atom.
(iii) The scattering of different α-particles through different angles on the nuclear model of the atom as below.
The α-particles such as a and a',which pass through the atom at a large distance from the nucleus experiences a small electrostatic force of repulsion due to the nucleus and hence undergo a very small deflection. The α-particles b and b1 which pass through the atom at a close distance from the nucleus suffer a large deflection.The α-particles such as C, which travels towards the nucleus directly, shows down as it moves and ultimately comes to rest and than after being deflected through 180°, retraces it path.
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Khushi Choudhary 3 years, 9 months ago
0Thank You