An iron tank 20 m long …

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Gaurav Seth 5 years ago
Given that length of the open iron tank = 20 m.
Breadth of the closed iron tank = 10 m
The height of the closed iron tank = 8 m.
Surface Area of the tank = 2[ bh + hl]
= 2[10×8+8×20] = 2×240=480m^2
Area of the rectangular iron sheet = 480m^2
so that length × breadth = 480m^2
But breadth of sheet = 4 m (given)
∴ length = 480 / 4 = 120 m .
Given that cost of iron, the sheet used at the rate of Rs 5 per metre.
The total cost of the sheet = Rs. (120 × 5) = Rs. 600.
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