How many atoms of Na will …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by P A 3 years, 9 months ago
- 2 answers
Gaurav Seth 3 years, 9 months ago
Explanation:
Molar mass of Na=23g/mol
no. of moles = weight/molar mass
n = 11.5/23
no. of moles = 0.5
no. of moles = no. of atoms/avogadro’s number
0.5 = no. of atoms/6.022*10^23
0.5*6.022*10^23 atoms = no. of atoms
3.011*10^23 atoms.
So there are 3.011*10^23 atoms present in 11.5g of sodium sample
Related Questions
Posted by Abhi Sandhu 1 month, 4 weeks ago
- 1 answers
Posted by Op Garg 2 months, 1 week ago
- 2 answers
Posted by Mukesh Mendon 2 months ago
- 1 answers
Posted by Huda Fatima 2 months, 1 week ago
- 2 answers
Posted by Anmol Kumar 2 months, 1 week ago
- 0 answers
Posted by Yash Dwivedi 2 months, 1 week ago
- 3 answers
Posted by Samir Chakma 1 month ago
- 0 answers
Posted by Himanshi Sharma 2 months, 1 week ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 3 years, 9 months ago
Molar mass of Na=23g/mol
no. of moles = weight/molar mass
n = 11.5/23
no. of moles = 0.5
no. of moles = no. of atoms/avogadro’s number
0.5 = no. of atoms/6.022*10^23
0.5*6.022*10^23 atoms = no. of atoms
3.011*10^23 atoms.
So there are 3.011*10^23 atoms present in 11.5g of sodium sample.
0Thank You