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A bullet of mass 10g moving …

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A bullet of mass 10g moving with velocity 400m/s imbidiant in freely suspended wooden block of mass 900g what is the velocity occurred by the block
  • 1 answers

Gaurav Seth 3 years, 9 months ago

We are given that a bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g.

 

Let the final velocity acquired by the block be 'v m/s'.

The mass of the bullet =  = 10 g = 

                                              = 0.01 kg

The mass of the wooden block =  = 900 g = 

                                                    = 0.9 kg

Also, the initial velocity of the bullet is given by =  = 400 m/s

and  the initial velocity of the wooden block is given by =  = 0 m/s

 

Now, the momentum conservation of law states that;

Momentum before collision = Momentum after collision

  =  

  =   = 4.4

 

So, v = 4.4 m/s which means this is the velocity acquired by the block.

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