A bullet of mass 10g moving …
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Gaurav Seth 4 years, 9 months ago
We are given that a bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g.
Let the final velocity acquired by the block be 'v m/s'.
The mass of the bullet =
= 10 g = 
= 0.01 kg
The mass of the wooden block =
= 900 g = 
= 0.9 kg
Also, the initial velocity of the bullet is given by =
= 400 m/s
and the initial velocity of the wooden block is given by =
= 0 m/s
Now, the momentum conservation of law states that;
Momentum before collision = Momentum after collision
=%2B%20(0.9%5Ctimes%200)%7D%7B(0.01%2B0.9)%7D)
=
= 4.4
So, v = 4.4 m/s which means this is the velocity acquired by the block.
2Thank You