A bullet of mass 10g moving …
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Gaurav Seth 3 years, 9 months ago
We are given that a bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g.
Let the final velocity acquired by the block be 'v m/s'.
The mass of the bullet = = 10 g =
= 0.01 kg
The mass of the wooden block = = 900 g =
= 0.9 kg
Also, the initial velocity of the bullet is given by = = 400 m/s
and the initial velocity of the wooden block is given by = = 0 m/s
Now, the momentum conservation of law states that;
Momentum before collision = Momentum after collision
=
= = 4.4
So, v = 4.4 m/s which means this is the velocity acquired by the block.
2Thank You