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The Floor Of a building consists …

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The Floor Of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor , if the cost per m² is Rs 4.......Plz Solve And Give Me Explanation.
  • 2 answers
d1= 45cm , d2= 30cm Number of tiles= 3000 Rate per m²= ₹4 Area of Rhombus= 1/2×d1×d2 = (1/2) × 45 × 30=675 Area of 1 tile= 675 cm² = 675/10000 m² Area of 3000 tiles= 3000 × (675/10000) [1cm²= 1/10000m²] cost of Polishing the floor = Total Area × rate = (3000 × 675 ×4)/10000 = 3× 675×4/10 = 3× 67.5×4 = 12× 67.5 = ₹ 810 Hence the total cost of polishing the floor = ₹ 810

Yogita Ingle 5 years ago

d1= 45cm , d2= 30cm

Number of tiles= 3000

Rate per m²= ₹4

Area of Rhombus= 1/2×d1×d2

= (1/2) × 45 × 30=675

Area of 1 tile= 675 cm² = 675/10000 m²

Area of 3000 tiles= 3000 × (675/10000)

[1cm²= 1/10000m²]

cost of Polishing the floor
= Total Area × rate

= (3000 × 675 ×4)/10000

= 3× 675×4/10

= 3× 67.5×4

= 12× 67.5

= ₹ 810

Hence the total cost of polishing the floor = ₹ 810

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