A ship is moving at a …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Vedprakash Pandey 5 years ago
- 4 answers
Gaurav Seth 5 years ago
Given:
Method I:
Initial speed=u=56km/h=56 x 5/18=15.55m/s
Final speed=v=58km/h=58x5/18=16.11m/s
Time=t=1sec
acceleration=a=?
as we know that acceleration is rate of change of velocity.
a=(v-u)/t
=(16.11-15.55)/1
=0.56 m/s²
Method 2:
Initial speed=u=56km/h
Final speed=v=58km/h
Time=t=1/60x60 h
acceleration=a=?
as we know that acceleration is rate of change of velocity.
a=(v-u)/t
=(58-56)/1/60*60
=2x3600
=7200 Km/h²
∴ Acceleration is 0.56 m/s² or 7200 Km/h²
Related Questions
Posted by Op Garg 1 year, 4 months ago
- 2 answers
Posted by Prasanna Mendon 4 months, 4 weeks ago
- 1 answers
Posted by Himanshi Sharma 1 year, 4 months ago
- 0 answers
Posted by Yash Dwivedi 1 year, 4 months ago
- 3 answers
Posted by Huda Fatima 1 year, 4 months ago
- 2 answers
Posted by Moksh Bhatia 1 year, 4 months ago
- 0 answers
Posted by Anmol Kumar 1 year, 4 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sara Tonger 5 years ago
1Thank You