Rationalnumbers, exercise, 1.2,solutions

1. Represent these numbers on the number line.

(i) 7/4

(ii) -5/6

Solution:

(i) 7/4

Divide the line between the whole numbers into 4 parts. i.e., divide the line between 0 and 1 to 4 parts, 1 and 2 to 4 parts and so on.

Thus, the rational number 7/4 lies at a distance of 7 points away from 0 towards positive number line.

(ii) -5/6

Divide the line between the integers into 4 parts. i.e., divide the line between 0 and -1 to 6 parts, -1 and -2 to 6 parts and so on. Here since the numerator is less than denominator, dividing 0 to – 1 into 6 part is sufficient.

Thus, the rational number -5/6 lies at a distance of 5 points, away from 0, towards negative number line

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<a data-ved="2ahUKEwjL0MyW6MPtAhV3xTgGHcyjCcUQFjAIegQIChAC" href="https://mycbseguide.com/blog/ncert-solutions-for-class-8-maths-exercise-1-2/" ping="/url?sa=t&source=web&rct=j&url=https://mycbseguide.com/blog/ncert-solutions-for-class-8-maths-exercise-1-2/&ved=2ahUKEwjL0MyW6MPtAhV3xTgGHcyjCcUQFjAIegQIChAC" rel="noopener" target="_blank">NCERT Solutions for Class 8 Maths Exercise 1.2 ...</a>