The sum of digits of two …

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Yogita Ingle 5 years ago
let digit at ones place=x and
digit at tens place=y
So, the number will be 10y+x
x+y=7 ....(1)
reverse digit will be represented as, 10x+y
So, (10x+y)-(10y-x)=27
9x-9y=27
x-y=3 ....(2)
Adding equation (1) and (2)
2x=10
x=5
substituting in equation (1)
y=7-5
=2
Thus, the number will be 25
1Thank You