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A person jumps onto a cement …

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A person jumps onto a cement floor from a height of 1m and comes to rest in 0.1s . The same person on jumping from a height of 9m into a sand pit comes to rest in 1s . Compare the forces exerted on him by cement floor and sand pit

Posted by Muskan Singh 3 years, 9 months ago

CBSE > Class 09 > Science

1 answers

Yogita Ingle 3 years, 9 months ago

h=1 m. h'=9 m.

t=0.1 s. t'=1 s.

Now force exerted in first case be F and in second case be F'.

Let the mass of man be m.

F= ma = m(change in velocity/change in time) = m(v-0)/t = m(sqrt(2gh))/t

F'=m(sqrt(2gh'))/t'

=> F/F'= sqrt(h/h')*t'/t

=>F/F'= sqrt(1/9) *1/0.1 = 10/3

Hence , F'=(3/10)F.

1Thank You

ANSWER

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