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Find the perimeter of a rhombus …

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Find the perimeter of a rhombus whose diogonals measure 12 cm and 16 cm respectively.
  • 1 answers

Gaurav Seth 5 years ago

Diagonal of rhombus = 12cm and 16cm

half of diagonal = 6cm and 8cm

by using Pythagoras theorem

at the point o where diangonals are meet at that point there are angle formed 90°
so,

a (side) of rhombus = √p² + b²

a = √6² + 8² = √36+64 =√ 100 = 10cm

now , as we know that Perimeter of rhombus

= 4a = 4×10 = 40cm Ans

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