Find the area of a rhombus …

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Posted by Sundram Jha 5 years ago
- 1 answers
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Gaurav Seth 5 years ago
In every rhombus, diagonal are perpendicular and bisect each other
Take rhombus as ABCD and bisecting point of diagonals as O
In every rhombus all sides are equal
So AB=BC=CD=DA=5cm
One diagonal is 6cm let AC
OA=OC=3cm
Since it is perpendicular so Pythagorean property applies
(OA)^2+(OB)^2=(AB)^2
=3^2+OB^2=5^2
=9+OB^2=25
=OB^2=25-9=16
=OB=4
Since OB+OD=BD
Then 4cm+4cm=8cm....OB and OD are equal
Area of rhombus=1/2×(d1×d2)
=1/2×(6×8)
=24cm2
1Thank You