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5(y-1)=3(2y-5)-(1-3y)

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5(y-1)=3(2y-5)-(1-3y)

Posted by Maku Sarmah 5 years ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years ago

5(y-1)=3(2y-5)-(1-3y)

5y - 5 = 3(2y) - 3 (5) - 1 + 3y

5y - 5 = 6y - 15 - 1 + 3y

5y - 5 = 9y - 16

5y - 9y = - 16 + 5

- 4y = - 11

y = 11/4

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CBSE > Class 08 > Mathematics