How much of 0.3 M ammonium …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Prabhnoor Kaur 5 years, 1 month ago
- 2 answers
Yogita Ingle 5 years, 1 month ago
Let V mL of NH4OH be mixed with NH4CI to have a buffer of pH 8.65. The total volume after mixing becomes (V+ 30) mL.
m Mole of NH4OH = 0.3×V
Thus, NH4OH = 0.3×V/ (v+30)
m Mole of NH4CL = 0.2×30
Thus, NH4CL = 0.2×30/ (v+30)
= 0.2×30/ (v+30)/ 0.3×V/ (v+30)
= 0.61 = log6 /0.3×V
= v = 4.91mL
Similarly,
14-10 = 4.74+log 0.2×30/ (v+30)/ 0.3×V/ (v+30)
for ph = 10
V = 109.9mL
Test
Related Questions
Posted by Shaila Bombe 1 year, 5 months ago
- 1 answers
Posted by Parneet Kaur 1 year, 1 month ago
- 0 answers
Posted by Naman Mehra 1 year, 5 months ago
- 0 answers
Posted by "Serai✨ Wallance" 1 year, 5 months ago
- 0 answers
Posted by Rihan Mehta 1 year, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 5 years, 1 month ago
How much of 0.3 M ammonium hydroxide should be mixed with 30 ml of 0.2 M solution of ammonium chloride to give buffer solutions 10 pH 8.65 and 10. Given pKb of NH4OH = 4.75.
A n s w e r :
Let V mL of NH4OH be mixed with NH4CI to have a buffer of pH 8.65. The total volume after mixing becomes (V+ 30) mL.
1Thank You