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Factorise : x²-17x+60

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Factorise : x²-17x+60

Posted by Tanupreet Kaur 5 years, 1 month ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

In the given polynomial x²−17x+60,

The first term is x² and its coefficient is 1.

The middle term is −17x and its coefficient is −17.

The last term is a constant term 60.

Multiply the coefficient of the first term by the constant 1×60=60.

We now find the factor of 60 whose sum equals the coefficient of the middle term, which is −17 and then factorize the polynomial x²−17x+60 as shown below:

x²−17x+60=x²−12x−5x+60=x(x−12)−5(x−12)=(x−5)(x−12)

Hence, x²−17x+60=(x−5)(x−12).

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CBSE > Class 08 > Mathematics