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Factorise : z²-7z-30

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Factorise : z²-7z-30
  • 1 answers

Gaurav Seth 5 years, 1 month ago

Factoring  z2-7z-30 

The first term is,  z2  its coefficient is  1 .
The middle term is,  -7z  its coefficient is  -7 .
The last term, "the constant", is  -30 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -30 = -30 

Step-2 : Find two factors of  -30  whose sum equals the coefficient of the middle term, which is   -7 .

      -30    +    1    =    -29  
      -15    +    2    =    -13  
      -10    +    3    =    -7    That's it


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -10  and  3 
                     z2 - 10z + 3z - 30

Step-4 : Add up the first 2 terms, pulling out like factors :
                    z • (z-10)
              Add up the last 2 terms, pulling out common factors :
                    3 • (z-10)
Step-5 : Add up the four terms of step 4 :
                    (z+3)  •  (z-10)

 

Hence, z2−7z−30=(z−10)(z+3).

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