Factorise : z²-7z-30

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Gaurav Seth 5 years, 1 month ago
Factoring z2-7z-30
The first term is, z2 its coefficient is 1 .
The middle term is, -7z its coefficient is -7 .
The last term, "the constant", is -30
Step-1 : Multiply the coefficient of the first term by the constant 1 • -30 = -30
Step-2 : Find two factors of -30 whose sum equals the coefficient of the middle term, which is -7 .
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 3
z2 - 10z + 3z - 30
Step-4 : Add up the first 2 terms, pulling out like factors :
z • (z-10)
Add up the last 2 terms, pulling out common factors :
3 • (z-10)
Step-5 : Add up the four terms of step 4 :
(z+3) • (z-10)
Hence, z2−7z−30=(z−10)(z+3).
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