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Derive the second equation of motion …

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Derive the second equation of motion graphically
  • 2 answers

Zainab Khan 3 years, 10 months ago

By velocity - time graph Firstly, AO=DC=U BC=V OT=AD=t Now, a=change in velocity/ time taken a= BC - CD/ AD (BD=BC - CD) a=v-u/t v-u=at v=u+at Answer

Yogita Ingle 3 years, 10 months ago

Velocity-Time Relation

  • A car having initial velocity u , is being subjected to a uniform acceleration a for a time period of t , after the time t the final velocity of the car is v.
  • Now we need to find the relation between v,u,a,t graphically.

Position-Time Relation

  • A car having initial velocity u , is being subjected to a uniform acceleration a for a time period of t , after the time t the final velocity of the car is v.
  • In the time interval of time t , it covers a distance of s.
  • Now we need to derive relation between s,u,a,t graphically.

 

 

Position–Velocity Relation

  • A car having initial velocity u , is being subjected to a uniform acceleration a for a time period of t , after the time t the final velocity of the car is v.
  • In the time interval of time t , it covers a distance of s.
  • Now we need to find relation between s,u,v,a graphically.

 

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